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3 years ago

Need help dont know which one to chose

Mathematics

1 answer:

Vlada [557]3 years ago

5 0

Answer:

the answer to this problem is A

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You can use a volume calculator

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Answer:

wasting your points but hey these are the answers

Step-by-step explanation:

1) 72

2) 2

3) 30

4) 2

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Cuanto es 20 + 20 porfa ayuda

umka2103 [35]

40 is the answer for the equation 20+20=40

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The angle 0 lies in Quadrant II . <br>Cos 0 = <br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexF

mel-nik [20]

Answer:

$\tan(\theta)=\frac{-\sqrt{5}}{2}$

Step-by-step explanation:

Since we are in quadrant 2, sine is positive. Since sine is positive and cosine is negative, then tangent is negative.

Now I'm going to find the sine value of this angle given using one of the Pythagorean Identities, namely $\sin^2(\theta)+\cos^2(\theta)=1$ .

If given $\cos(\theta)=\frac{-2}{3}$ , then we have $\sin^2(\theta)+(\frac{-2}{3})^2=1$ by substitution of $\cos(\theta)=\frac{-2}{3}$ .

Let's solve:

$\sin^2(\theta)+(\frac{-2}{3})^2=1$ for $\sin(\theta)$ .

$\sin^2(\theta)+\frac{4}{9}=1$

Subtract 4/9 on both sides:

$\sin^2(\theta)=1-\frac{4}{9}$

Simplify:

$\sin^2(\theta)=\frac{5}{9}$

Square root both sides:

$\sin(\theta)=\sqrt{\frac{5}{9}}$

$\sin(\theta)=\frac{\sqrt{5}}{\sqrt{9}}$

$\sin(\theta)=\frac{\sqrt{5}}{3}$

===========

$\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=\frac{\frac{\sqrt{5}}{3}}{\frac{-2}{3}}$

Multiplying top and bottom by 3 gives:

$\tan(\theta)=\frac{\sqrt{5}}{-2}$

I'm going to move the factor of -1 to the top:

$\tan(\theta)=\frac{-\sqrt{5}}{2}$

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3 years ago

1a.Given: B is the midpoint of AC.<br> B<br> If AC = 17, find BC.

Fudgin [204]

Answer: BC = 8.5

Step-by-step explanation:

Since B is the midpoint (or middle), then AB and BC are equal to each other.

Simply divide AC by 2 to find BC

AC = 17

17/2 = 8.5

Therefore, BC = 8.5

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