Question

15 POINTS - What is the value of the expression when y=2? See image.

Answer 1

Answer:

6

Step-by-step explanation:

The given expression is;

$\frac{2-y}{4+y}+\frac{3(y+2)}{y}$

When y=2, the expression becomes;

$\frac{2-2}{4+2}+\frac{3(2+2)}{2}$

This simplifies to;

$\frac{0}{6}+\frac{3(4)}{2}$

$0+3(2)$

Multiply to get;

$0+6=6$

The value of the expression when y=2 is 6.