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Salsk061 [2.6K]
3 years ago
5

A fair number cube is rolled, and a fair coin is tossed. Compare the probabilities. Choose from the symbols given.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

C

There are an even amount of sides on each object.

Step-by-step explanation:

<em>It izz wat it izzzz!!!</em>

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const2013 [10]
This is high school this is for my sister since she is in apex um lets see. actually can't see. sorry
5 0
3 years ago
Need help solving these two vector problems.
jonny [76]
<h3>Answer:</h3>

see below

<h3>Step-by-step explanation:</h3>

Here, we'll use an ordered pair <a, b> to represent each vector's two components. The rules are ...

  • multiplying a vector by a scalar multiplies each component by that scalar
  • multiplying a vector by a scalar multiplies its magnitude by the magnitude of the scalar
  • the magnitude of a vector is the square root of the sum of the squares of its components
<h2>1.</h2>

For A = <2.5, -3.5>, |A| = √(2.5²+(-3.5)²) = √18.5 ≈ 4.30

  • 2A = <5, -7>; |2A| = 8.60
  • -2A = <-5, 7>; |-2A| = 8.60
  • A/2 = <1.25, -1.75>; |A/2| = 2.15

_____

<h2>2.</h2>

A = |A|<cos(43.9°), sin(43.9°)>

B = |B|<cos(154.8°), sin(154.8°)>

C = <0, -25.8>

The sum being zero gives rise to 2 equations in 2 unknowns.

  |A|cos(43.9°) +|B|cos(154.8°) = 0

  |A|sin(43.9°) +|B|sin(154.8°) = 25.8

Using Cramer's rule to find the solution, we get ...

  |A| = 25.8cos(154.8°)/(cos(154.8°)sin(43.9°) -sin(154.8°)cos(43.9°))

  |A| = 25.8cos(154.8°)/sin(43.9° -154.8°)

  |A| ≈ 24.9887

  |B| = -25.8cos(43.9°)/sin(-110.9°)

  |B| ≈ 19.8995

4 0
3 years ago
Fill in the blanks with two rational numbers (other than 1 and −1).
MA_775_DIABLO [31]

Answer:

2 and 20

Step-by-step explanation:

First how can we get rid of the fraction?

We can multiply -1/2 by 2 to get -1

Next what number do we multiply to get from -1 to -20?

-1x = -20

divide both sides by -1

x = 20

please give thanks by clicking the heart :)

7 0
3 years ago
Find the area of the triangle below.
d1i1m1o1n [39]

Answer:

   45.5

Step-by-step explanation:

Use pyth theorem to find the whole bottom side. Then sub 16 by 13. # is the small segmented area. The small segmented tri is 10.5 area. The big tri is 56. Sub 10.5 from 56 to get 45.5.

4 0
2 years ago
United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res
Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so n = 200.

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So \pi = 0.0995.

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find P(X < 18), with \pi = 0.0995, n = 200. We can use a binomial probability calculator, and we find that:

P(X < 18) = 0.2927.

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

5 0
3 years ago
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