True or False: The relation {(3, 2), (1, 2), (7, –5), (11, 6), (17, –4), (13, 8)} is a function.
8090 [49]
Answer:
False
Step-by-step explanation:
This is because if you have a function which is Y=2x-4 , then trying to give an example using the given points which (3,2) , here we will have Y=2 upon replacing 3 in the function cause 3 is the value of x and vice versa if we have 2 as the value of Y then x will be 3 . However,if we get the (1,2) the answer for Y will be -2 which is different from the one we have in the question hence this concludes false
Answer:
S=a^2
Step-by-step explanation:
Note all sides of a square are equal, and the formula for finding the area is length x width of which the length=a and the with =a. So S=a^2.
From a formula located here:
http://www.1728.org/quadltrl.htm
we see that
<span>4 • Side² = Long Diagonal² + Short Diagonal²
Long Diagonal = 24
Short Diagonal = 10
</span><span>4 • Side² = 24^2 + 10^2 </span>
<span>4 • Side² = 576 + 100
</span><span>4 • Side² = 676
</span><span><span>Side²</span> = 169
Side (or line AB) = 13
</span>
Answer:
x = 8
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
= 
Note that ΔBCD is a 3- 4- 5 triangle ( Pythagorean triple), hence CD = 4
Substitute given values into the equation
= 
( cross- multiply )
3x = 24 ( divide both sides by 3 )
x = 8
Answer:
- amount lent: ₹6000
- interest received: Kamal, ₹600; Anand, ₹615.
Step-by-step explanation:
For principal P invested at simple interest rate r, the returned value in t years is ...
A = P(1 +rt)
If K is Kamal's returned value, the given numbers tell us ...
K = P(1 +0.05·2) = 1.1P
__
For principal P invested at compound interest rate r, with interest compounded annually for t years, the returned value is ...
A = P(1 +r)^t
If A is Anand's returned value, the given numbers tell us ...
A = P(1.05)² = 1.1025P
This latter amount is RS.15 more than the former one, so we have ...
1.1025P = 1.1P +15
0.0025P = 15 . . . . . . . . subtract 1.1P
P = 6000 . . . . . . . . . . . divide by 0.0025 . . . . the amount lent
Kamal received 1.1P -P = 0.1P = 600 on the investment.
Each lent ₹6000. Kamal received ₹600 in interest; Anand received ₹615 in interest.
