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3 years ago

NEED HELP ASAP <3

1 answer:

4 0

Triangle squares and hexagons are the Only regular shapes which tessellate by themselves. You can have other tessellations of regular shapes if you use more than one type of shape. You can even tessellate pentagons, But they won’t be regular ones.

Would appreciate if given brainliest:)

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CAN SOMEONE PLEASE HELP ME

Dvinal [7]

The answer is D hope this helped

6 0

3 years ago

Based on Charles Waddell Chestnutt's "The Wife Of His Yout. Which of the following statements about Mr. Ryder is true? Choose al

Serjik [45]

I'm pretty sure that there are two statements which are true: b. At the conclusion of the story, Charles Waddell Chesnutt wants readers to see the redeeming qualities in Mr. Ryder. and c. The wife of Mr. Ryder's youth could never be a member of his exclusive society.

3 0

3 years ago

Find the diameter of the circle (x-4)2 + (y + 6)2 = 16. A)2 B)4 C)8 D)16

Rzqust [24]

Answer:

The answer is C ) 8

As square root of 16 is 4 which is radius

So times that by 2 gives you 8

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please answer this question I can't seem to figure it out I have even asked my parents.

nika2105 [10]

Answer:

j. Pam, Tia, Veronica, Lily (if it's youngest to oldest)

Step-by-step explanation:

If Tia is 8 yrs old and she's 2 yrs older than Pam, then Pam must be 6 yrs old. Pam si 5 yrs younger than Veronica who must be 11 + 4 = 15.

Tia: 8 yrs.

Veronica: 11 yrs

Pam: 6 yrs.

Lily: 15

4 0

2 years ago

Read 2 more answers

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

Step-by-step explanation:

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

3 years ago