The inequality can be used to determine how many months will it take for Caroline's hair to be at least as long as Trinity's hair is (1/5)x + 7 ≥ (1/10)x + 10
<h3>What is an
equation? </h3>
An equation is an expression that shows the relationship between two or more numbers and variables. An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.
Let x represent the number of months.
For Caroline's hair:
Length = (1/5)x + 7
For Trinity's hair:
Length = (1/10)x + 10
For Caroline's hair to be at least as long as Trinity's hair, hence:
(1/5)x + 7 ≥ (1/10)x + 10
The inequality can be used to determine how many months will it take for Caroline's hair to be at least as long as Trinity's hair is (1/5)x + 7 ≥ (1/10)x + 10
Find out more on equation at: brainly.com/question/2972832
#SPJ1
52/3 - 10
Convert both numbers into fractions.
52/3 - 10/1
Make sure they both have the same denominator
52/3 - 30/3
Now you can take the numerator and subtract it.
22/3
Now you simply simplify
7 1/3
So the answer is 7 1/3
Answer: See explanation
Step-by-step explanation:
Let the number of hamburger he ate on Monday be represented by x.
Monday = x
Tuesday = 0
Wednesday = x + 4
Thursday = 0
Friday = 3(x + 4)
Total hamburgers ate = 26
To find the amount of hamburger ate each day we add the number of hamburger ate per day all together. This will be:
= x + 0 + x + 4 + 0 + 3(x+4) = 26
2x + 4 + 3x + 12 = 26
5x + 16 = 26
5x = 26 - 16
5x = 10
x = 10/5
x = 2
Monday = x = 2 hamburgers
Tuesday = 0
Wednesday = x + 4 = 2 + 4 = 6 hamburgers
Thursday = 0
Friday = 3(x + 4) = 3(2 + 4) = 18 hamburgers
Answer:
the scale factor is 4 to 1, or just 4.
Step-by-step explanation:
Step-by-step explanation:
(x^4)^3=(x^3)^4 , true
=> x^(4×3) = x^(3×4) = x^12
13^4 x 13^7= (13^4)^7, false
13^(4+7) = 13^11
(13^4)^7 = 13^(4×7) = 13^28
y^5 x y^0/y^3=(y^2)^1 , true
y^5 x y^0/y^3 = y^(5+0-3) = y^2
(y^2)^1 = y^(2×1) = y^2
q^0 x q^5/q^2=(q^3)^2/q^3, true
q^0 x q^5/q^2= q^(0+5-2)= q^3
(q^3)^2/q^3 = q^(3×2-3) = q^3
