Answer:
The probability is 
Step-by-step explanation:
Let assume that the number of computer produced by factory C is k = 1
So From the question we are told that
The number produced by factory A is 4k = 4
The number produced by factory B is 7k = 7
The probability of defective computers from A is 
The probability of defective computers from B is 
The probability of defective computers from C is 
Now the probability of factory A producing a defective computer out of the 4 computers produced is

substituting values


The probability of factory B producing a defective computer out of the 7 computers produced is

substituting values


The probability of factory C producing a defective computer out of the 1 computer produced is

substituting values


So the probability that the a computer produced from the three factory will be defective is

substituting values


Now the probability that the defective computer is produced from factory A is



I hope this helps you
m (R)=m (L)
m (S)=m (M)
m (T)=m (N)
Answer:
Population of dice mice after one year = 2000
Population of wood rats after one year = 1000
The population of deer mice is growing faster than the popular of wood rats
Step-by-step explanation:
The expression for population = dN/dt = rN
Upon integration N = rN²/2
Therefore for population N = 200 and r= 0.1
N after one year = (0.1 x 200²)/ 2 = 2000
Therefore for population N = 100 and r= 0.2
N after one year = (0.2 x 100²)/ 2 = 1000
Hence the population of deer mice is growing faster than the popular of wood rats
Answer:
5^2x
Step-by-step explanation:
write the number in exponential form with a base of 5
(5^2)^x
simplify the expression by multiplying exponents
5^2x
Answer:
P = 309.35 + 2.31t
Step-by-step explanation:
The relation between the population of the USA and the time in years after 2010 will be linear as the increase in population is constant for every year since 2010 which is 2.31 million.
So, we can model the population P in million as a function of time(t) in years since 2010 as
P = 309.35 + 2.31t ....... (1)
Now, for t = 0 i.e. in the year 2010, the population will be obtained from equation (1) to be 309.35 million.
(Answer)