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2 years ago

Can sum one help me please

Mathematics

2 answers:

const2013 [10]2 years ago

8 0

Answer:

scale facror:

x = 5

Perimeter = 5+4+4+5+6 = 24

Elanso [62]2 years ago

8 0

THEBECKS is correct but can we please talk about the pictures in the background LOLL i-

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What is the equation of the line passing through the points (Two-fifths, StartFraction 19 Over 20 EndFraction) and (one-third, S

Neporo4naja [7]

Answer:

y = one-half x + three-fourths

Step-by-step explanation:

The 2-point form of the equation of a line can be used for starters.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (11/12 -19/20)/(1/3 -2/5)(x -2/5) +19/20 . . . . fill in given values

y = ((55 -57)/60)/((5 -6)/15)(x -8/20) +19/20 . . simplify a little

y = (-1/30)/(-2/30)(x -8/20) +19/20 . . . . . . . . . . and a little more ...

y = 1/2x -4/20 +19/20

y = 1/2x +15/20

y = 1/2x +3/4 . . . . line in slope-intercept form

8 0

3 years ago

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The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.

puteri [66]

Answer:

$\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Area of a Rectangle: A = lw

l is length
w is width

Calculus

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle l = 10 \ meters$

$\displaystyle \frac{dl}{dt} = 4 \ m/day$

$\displaystyle w = 23 \ meters$

$\displaystyle \frac{dw}{dt} = 1 \ m/day$

Step 2: Differentiate

[Area of Rectangle] Product Rule: $\displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}$

Step 3: Solve

[Rate] Substitute in variables [Derivative]: $\displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)$
[Rate] Multiply: $\displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day$
[Rate] Add: $\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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3 years ago

Please answer me bis two fifths of c. 4a = 30 Work out the ratio a:b:c Give your ans

irina [24]

b is two fifths of c, so we make this a ratio with c = 1.

The ratio of b:c is 2/5 : 1

We also have 4a = 3c, rewrite this ratio so c is 1 by dividing both sides by 4,

so we get the ratio of a to c as 3/4 : 1

Now we get the a:b:c ratio of 3/4 : 2/5 : 1 now we can change the fractions to whole numbers, first by multiplying the 3 numbers by 4 to get get rid of the denominator of 4 in a:

3 : 8/5 : 4

Now multiply the 3 numbers by 5 to remove the denominator of 5 in b:

15 : 8 : 20

Now we can check using the equations:

b is 2/5 of c: 20 x 2/5 = 40/5 = 8 This is true.

4a = 3c: 4(15) = 3(20) = 60 = 60, this is also true.

The ratios is 15 : 8: 20

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3 years ago

Which of the following expressions is equivalent to -9?

FromTheMoon [43]

B because there is only one negative and -63 divided by 7 equals -9. If it were -7 divided by 63 that would give you an answer in decimal form.

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3 years ago

I need help with numbers 6 and 7

ella [17]

I need to see more of the picture

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3 years ago

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