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nordsb [41]
3 years ago
5

The half–life of rubidium–89 is 15 minutes. If the initial mass of the isotope is 250 grams, how many grams will be left after 1

00 minutes?
Mathematics
2 answers:
nikitadnepr [17]3 years ago
8 0

Answer:

32.5 grams  will be left after 100 minutes.                        

Step-by-step explanation:

Given : The half–life of rubidium–89 is 15 minutes. If the initial mass of the isotope is 250 grams.

To find : How many grams will be left after 100 minutes?          

Solution :

Let the exponential equation of rubidium is Q=Q_oe^{rt}

Where, Q_o=250 is the initial value

t is the time taken i.e. t=15 minutes

The half–life of rubidium–89 is 15 minutes.

i.e. Q=\frac{Q_o}{2}

Substitute in the formula,

\frac{Q_o}{2}=Q_oe^{r\times 15}

\frac{1}{2}=e^{r\times 15}

Taking log both side,

\log (\frac{1}{2})=r\times 15

-0.301=r\times 15

\frac{-0.301}{15}=r

r=-0.02

Now, we have to find Q in 100 minutes,

Q=Q_oe^{rt}

Substitute in the formula,

Q=250e^{-0.02\times 100}

Q=250e^{-2}

Q=250\times 0.13

Q=32.5

Therefore, 32.5 grams  will be left after 100 minutes.

irina1246 [14]3 years ago
5 0
M(100) = 2.46 grams    . 
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Fudgin [204]

Answer:

The ball reached its maximum height of (11\ yards) in (1\ second).

Step-by-step explanation:

This question is essentially asking one to find the vertex of the parabola formed by the given equation. One could plot the equation, but it would be far more efficient to complete the square. Completing the square of an equation is a process by which a person converts the equation of a parabola from standard form to vertex form.

The first step in completing the square is to group the quadratic and linear term:

h(t)=-5t^2 + 10t + 6\\\\h(t) = (-5t^2 + 10t) + 6

Now factor out the coefficient of the quadratic term:

h(t)=-5(t^2 -2t) + 6

After doing so, add a constant such that the terms inside the parenthesis form a perfect square, don't forget to balance the equation by adding the inverse of the added constant term:

h(t) = -5(t^2 -2t) + 6\\\\h(t) = -5(t^2 -2t + 1 -1 ) + 6

Now take the balancing term out of the parenthesis:

\\\\h(t)=-5(t^2 -2t + 1) + 6 + ((-1)(-5))

Simplify:

h(t) = -5(t^2 -2t + 1) + 6 + 5\\\\h(t) = -5(t-1)^2 + 11

The x-coordinate of the vertex of the parabola is equal to the additive inverse of the numerical part of the quadratic term. The y-coordinate of the vertex is the constant term outside of the parenthesis. Thus, the vertex of the parabola is:

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8 0
3 years ago
The midpoint of GH is M( 6,-4). One endpoint is G(8,-2). Find the coordinates of endpoint H.
Finger [1]

Using the midpoint formula, the coordinates of endpoint H are (4, -6).

<h3>The Midpoint Formula</h3>

The midpoint formula is given as: (x_m, y_m) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )

<em>Where</em>,

(x_m, y_m) = coordinates of the midpoint

(x_1, y_1) = coordinates of the first point

(x_2, y_2) = coordinates of the second point

Given the following:

(x_m, y_m) = M( 6,-4)

(x_1, y_1) = G(8,-2)

(x_2, y_2) = H(?, ?)

Plug in the values into the midpoint formula

M(6, -4) = (\frac{8 + x_2}{2}, \frac{-2 + y_2}{2} )

Solve for the x-coordinate and y-coordinate separately

6 = \frac{8 + x_2}{2}

  • Multiply both sides

6 \times 2 = 8 + x_2\\\\12 = 8 + x_2\\\\12 - 8 = x_2\\\\4 = x_2\\\\\mathbf{x_2 = 4}

-4 = \frac{-2 + y_2}{2}\\\\-8 = -2 + y_2\\\\-8 + 2 = y_2\\\\-6 = y_2\\\\\mathbf{y_2 = -6}

Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).

Learn more about midpoint formula on:

brainly.com/question/13115533

3 0
2 years ago
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The answer is -8 or a
7 0
3 years ago
Circle a has a radius of 3 and circle b has a radius of 11. if the idstance between the center of the circles in 17, find the le
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Answer: the length of the common external tangent is 15.

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