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Veronika [31]
3 years ago
8

A bag contains 3 red cards numbered 1-3 and 4 white cares numbered 1-4 you choose a card at random

Mathematics
1 answer:
melomori [17]3 years ago
7 0
So if your looking for any red card your odds are 43% if your looking for a white its 57%, and lets say as a ex you want red 3 your odds are about 14%
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A square has a perimeter of 12x 52 units. which expression represents the side length of the square in units? x 4 x 40 3x 13 3x
d1i1m1o1n [39]

The expression which represents the side length of the square which has perimeter of 12x 52 units is 3x+12 units.

<h3>What is the perimeter of a square?</h3>

The measure of the boundary of the sides of a square is called its perimeter. The perimeter of a square is 4 times the side of the square.

P=4a

Here, (<em>a</em>) is the side of the square.

A square has a perimeter of 12x +52 units. The perimeter of a square is 4 times the side of the square. Thus, the side of this square is,

P=4a\\12x +52=4a\\a=\dfrac{12x +52}{4}\\a=\dfrac{4(3x +12)}{4}\\a=3x+12

Thus, the expression which represents the side length of the square which has perimeter of 12x 52 units is 3x+12 units.

Learn more about the perimeter of the square here;

brainly.com/question/25092270

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2 years ago
How do I know if it's a function or not?
Effectus [21]
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5 0
3 years ago
Read 2 more answers
Tell whether (5, 2) is a solution of x - y &lt; 0.
meriva

Your points: (5,2)

Your inequality: x - y < 0

Plug 5 in for x and y in for 2

5 - 2 < 0.

Simplify the left side

3 < 0.

3 is not less than 0

(5,2) is not a solution of x - y < 0

5 0
3 years ago
1. The midpoint of the segment joining points (a, b) and ( j, k) is: a. (j-a,k-b) b. ((j-a)/2,(k-b)/2) c. (j+a,k+b) d. ((j+a)/2,
harkovskaia [24]
1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)

2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)

3. Point (-4, 3) lies in Quadrant II

4. Point (6, 0) lies on the x-axis

5. Any line with no slope is parallel to the y-axis

7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1

8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)

9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6

10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True

7 0
3 years ago
Read 2 more answers
PLEASEE HELP AND SHOW WORK IF YOU CAN​
monitta

Answer:

a

Step-by-step explanation:

6 0
3 years ago
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