Answer:
Acceleration, a = 6m/s²
Explanation:
<u>Given the following data;</u>
Mass = 62kg
Force = 372N
To find his acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
- F represents force.
- m represents the mass of an object.
- a represents acceleration.
Making acceleration (a) the subject, we have;

Substituting into the equation, we have;

<em>Acceleration, a = 6m/s²</em>
<em>Therefore, Zach accelerates at the rate of 6 meters per seconds square. </em>
Hello there.
<span>An understanding of the spacing effect provides insight into effective strategies for...
</span><span>A) rehearsal</span>
Answer:

Explanation:
We need to write the polar form of the given equation :

Put
and 
![x^2+(y-6)^2=36\\\\(r\cos\theta)^2+(r\sin\theta-6)^2=36\\\\r^2\cos^2\theta+r^2\sin^2\theta+36-12r\sin\theta=36\ \ [\because (a-b)^2=a^2+b^2-2ab]\\\\r^2(\cos^2\theta+\sin^2\theta)-12r\sin\theta=0\\\\\text{We know that}, \cos^2\theta+\sin^2\theta=1\\\\r^2-12r\sin\theta=1](https://tex.z-dn.net/?f=x%5E2%2B%28y-6%29%5E2%3D36%5C%5C%5C%5C%28r%5Ccos%5Ctheta%29%5E2%2B%28r%5Csin%5Ctheta-6%29%5E2%3D36%5C%5C%5C%5Cr%5E2%5Ccos%5E2%5Ctheta%2Br%5E2%5Csin%5E2%5Ctheta%2B36-12r%5Csin%5Ctheta%3D36%5C%20%5C%20%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2%2Bb%5E2-2ab%5D%5C%5C%5C%5Cr%5E2%28%5Ccos%5E2%5Ctheta%2B%5Csin%5E2%5Ctheta%29-12r%5Csin%5Ctheta%3D0%5C%5C%5C%5C%5Ctext%7BWe%20know%20that%7D%2C%20%5Ccos%5E2%5Ctheta%2B%5Csin%5E2%5Ctheta%3D1%5C%5C%5C%5Cr%5E2-12r%5Csin%5Ctheta%3D1)
Hence, the above is the polar form of the given equation i.e. 
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Answer:
I'm guessing it's a diploma.