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butalik [34]
3 years ago
7

What are the values of u and v

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

u=72

v=61

Step-by-step explanation:

for U:

54+54=108

180-108=72

For V:

180-58=122

122/2=61

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The answer is 0.1 hours = 6 minutes
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The greatest common factor of 3m2n + 12mn2 is
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3m^2n+12mn^2
In both the sets, 3 and m as well as n can be found as common factors.
So,
3mn( m+4n)


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Solve for x <br><br>x^3 - 3x = 0​
artcher [175]

Answer:

x^3-3x=0

+3x

x^3=3x

ok so that means that that number cubed is the same as a number squared so

x = 0

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The image of F(-5,-9) after translating along &lt;4, 6 &gt; and then translating along &lt; 3, 5&gt; is? F’(?,?)
dusya [7]
<h3>Answer:  (2, 2)</h3>

==============================================

Explanation:

The phrasing "translated along <4,6>" is another way of saying "shift 4 to the right, shift 6 up"

In general, "translated along <m,n>" is the same as writing (x,y) \to (x+m, y+n). If m is positive, then we shift m units to the right. If m is negative, then we shift to the left. The same story happens with the n, but we focus on the y coordinate.

-------------

With all that in mind, starting at F(-5,-9) and translating along <4,6> has us arrive at (-1, -3). Add 4 to the x coordinate and add 6 to the y coordinate.

We can say

(x,y) \to (x+4,y+6)\\\\(-5,-9) \to (-5+4,-9+6)\\\\(-5,-9) \to (-1,-3)\\\\

Showing that (-5,-9) moves to (-1,-3)

This is after the first translation, but there's a second translation.

We'll apply the same idea, but different numbers this time

(x,y) \to (x+3,y+5)\\\\(-1,-3) \to (-1+3,-3+5)\\\\(-1,-3) \to (2,2)\\\\

So (-1,-3) moves to (2,2)

Overall we have

  • (-5,-9) move to (-1,-3) after the first translation
  • (-1,-3) move to (2,2) after the second translation

Therefore, the original point ends up at (2,2) which is the final answer

--------------

Extra info:

A nice shortcut is that the vectors <4,6> and <3,5> can be added to get <4+3,6+5> = <7,11>. So overall, we're shifting 7 units to the right and 11 units up when we combine the two translation vectors.

5 0
3 years ago
HELP, ASAP PLEASE!!!!
algol13

Answer:Remember that the general formula of geometric sequence is 

where 

is the nth term

is the difference

is the place of the term in the sequence

Also, to find  we will use the formula: 

where 

is the current term in the sequence 

is the previous term 

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We know for our problem that the initial value of the computer is $1250, so our first term is 1250. In other words .

To fin our second term , we are going to subtract 10% of the value to our original value:

and , so 

To find our third term  we are going to subtract yet again 10% to our current value:

and , so

Now that we have our sequence  lets check if we have a consistent  to prove we have a geometric sequence:

- with , and :

 

- with , and :

 

Look! our s are the same, so we can conclude that we have a geometric sequence.

b) To do this we just need to replece the values of our sequence in the general formula of a geometric sequence. We know from our previous point that  and . So lets replace those values in geometric sequence formula to find our explicit formula:

c) To find the value of the computer at the beginning of the 6th year, we just need to find the 6th therm in our geometric sequence:

We can conclude that the value of the computer at the beginning of the 6th year will be $738.1125

Step-by-step explanation:

i did some research i dont know if it helped out not but id appreciate brainliest if it did..... thank you.

3 0
3 years ago
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