mei has eight jars of soup each jar of soup contains 300 milliliters of soup what is the smallest pot mei can use

You are dealt one card from a standard 52-card deck. Find the probability of being dealt an ace or a 6.

Ainat [17]

Answer:

2/13

Step-by-step explanation:

Since there's 4 of each card in the deck this means that there're 4 sixes and 4 aces, so 8 cards in a 52 card deck gives the problem 8/52 which equals 2/13

4 0

3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

How do you find degree measures? How would you solve this question?

MrRa [10]

A. a=145 b=35 c=145 d=145 e=35 f=145 g=35

b. These are the pairs of vertical angles: a & c, b & 35, d & f, e & g.

Hope this was helpful.

8 0

3 years ago

Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

4 0

3 years ago

A boutique prices merchandise by adding 80% to its cost. It later decreases by 25% the price of items that do not sell quickly

Darya [45]

A. Write a function f(x) to represent the price after the 80% markup.
b. Write a function g(x) to represent the price after the 25% markdown. 
c. Use a composition function to find the price of an item after both price adjustments that originally costs the boutique $150. 
d. Does the order in which the adjustments are applied make a difference? Explain.

answers

a) f(x) = 1.8x

b) f(x) = 0.75(1.8x)

c) f(150) = 0.75(1.8(150) = $202.50

d) No, it doesn't matter. The result is the same.

8 0

3 years ago