Question

Consider an espresso stand with a single barista. Customers arrive at the stand at the rate of 28 per hour according to a Poisson distribution. Service times are exponentially distributed with a service rate of 35 customers per hour. The average number of customers in the system (i.e., waiting and being served) is

Answer 1

Answer:

The average number of customers in the system is 3.2

Step-by-step explanation:

The average number of customes in the system is given by:

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

In which

$\lambda$ is the number of arirvals per time period

$\mu$ is the average number of people being served per period.

The number of arrivals is modeled by the Poisson distribution, while the service time is modeled by the exponential distribution.

Customers arrive at the stand at the rate of 28 per hour

This means that $\lambda = 28$

Service times are exponentially distributed with a service rate of 35 customers per hour.

This means that $\mu = 35$. So

The average number of customers in the system (i.e., waiting and being served) is

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

$L = \frac{28^{2}}{35(35 - 28)} = 3.2$

The average number of customers in the system is 3.2