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Troyanec [42]
2 years ago
12

Use benchmarks 3\5 + 3\17

Mathematics
2 answers:
nadya68 [22]2 years ago
3 0

Answer:

66/85

Step-by-step explanation:

QveST [7]2 years ago
3 0
3/15 Multiply both top and bottom by 17 to get 51/85
3/17 Multiply both top and bottom by 5 to get 15/85
Add
3/5+3/17
51/85+15/85
66/85
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2 years ago
The box plots below show attendance at a local movie theater and high school basketball games:
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Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
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Range = 150 - 60 = 90 (approx)
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Q3 = 120 (approx), third quartlie
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Basketball:
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Q2 = 125 (approx)
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Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
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Answer: D
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3 years ago
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What is the value of x
djyliett [7]

Check the picture below.

5 0
3 years ago
Can someone please do the highlighted questions? I suck at math. :(
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You'll need to offer wayyyyy more than 15 points :(
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