Can u guys plz give me ALL the following answers to graph 1.

Triangle ABC is rotated 45° about point X, resulting in triangle EFD. If EF = 4.2 cm, DF = 3.6 cm, and DE = 4.5 cm, what is CB?

Margaret [11]

This is the concept of transformations, given that ABC was rotated it implies that it retained it's original dimensions. This means that ABC is proportional to EFD. Therefore, given that EF=4.2 cm, DF=3.6 cm and DE=4.5 cm. The CB=FD=3.6 cm

5 0

3 years ago

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Please help me I will truly appreciate it

Gemiola [76]

Answer:

I think it is 7.6

the square root of 58 is 7.6

7.6 x2 = y y/2= 7.6 again

5 0

3 years ago

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A researcher wishes to estimate the average blood alcohol concentration (BAC) for drivers involved in fatal accidents who are f

Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean BAC = 0.16 g/dL

s = sample standard deviation = 0.080 g/dL

n = sample of drivers = 60

$\mu$ = population mean BAC in fatal crashes

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

So, a 90% confidence interval for the population mean, $\mu$ is;

P(-1.672 < $t_5_9$ < 1.672) = 0.90 {As the critical value of t at 59 degrees of

freedom are -1.672 & 1.672 with P = 5%} P(-1.672 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.672) = 0.90

P( $-1.672 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

<u>90% confidence interval for</u> $\mu$ = [ $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $0.16-1.672 \times {\frac{0.08}{\sqrt{60} } }$ , $0.16+1.672 \times {\frac{0.08}{\sqrt{60} } }$ ]

= [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0

3 years ago

The horizontal value at which the highest point of a variable's normal curve occurs is also the ____ of the variable.

inessss [21]

The answer to the question mentioned above is "the mean" such as the whole sentence will become "The horizontal value at which the highest point of a variable's normal curve is also the MEAN of the variable". This is the answer.

4 0

2 years ago

I need help. u need to answer. i need to see ur answer. u have to answer correctly. JKKK. but i need help :(

ElenaW [278]

Answer:

3x + 100 < 2x - 250

Step-by-step explanation:

The problem said that Keisha's guess was "250 less than twice the number".

It was written as 250-2x, which is actually twice the number less than 250, because we are subtracting 2x. We just need to write it like this:

2x-250

So the inequality should be:

3x + 100 < 2x - 250

5 0

3 years ago

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