Answer 2/13
Step-by-step explanation:
There are 52 cards in a standard deck: 13 ordinal cards (Ace -10, jack, Queen, King)and 4 of them
- one to each sute (hearts, diamonds, clubs, spades ) and so we have 4x13=52
There are 8 card that fit the question (4 each of access and kings).
so if you in a random draw the odds of drawing one of those 8 card out of the total number of 52 is 8/52
which we simplify
8/2=2/13
9514 1404 393
Answer:
24 m
Step-by-step explanation:
The area formula tells us ...
22 = xy . . . . . square meters
Adding twice this to the quadratic constraint gives ...
(x^2 +y^2) +2(xy) = (100) +2(22)
(x +y)^2 = 144
x +y = √144 = 12
The perimeter is double this amount, so is ...
P = 2(x +y) = 2(12) = 24 . . . . meters
Y= 2x+10 would be the equation and it would have no solution because there's no value if x nor y
Answer:
The fourth one: Gavin has one and thirteen fourteenths buckets of water. Daven has one and three fourteenths buckets of water. Together they have three and two fourteenths buckets of water.
Step-by-step explanation:
Gavin = 1 13/14
Daven = 1 3/14
1 13/14 + 1 3/14 = 2 16/14
2 16/14 = 3 2/14 = three and two fourteenths
Answer:
-I haven't done this, but I have copied and pasted from another question and answer from the user syed514:
Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.
If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.
Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.
Solving for the coordinates gives x2 = 10, y2 = 13
