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charle [14.2K]
3 years ago
6

I need help fast!!!!

Mathematics
2 answers:
Elena L [17]3 years ago
6 0
3q+21c

q=7

If this helped please give stars and a thanks ^.^ much appreciated!
NNADVOKAT [17]3 years ago
5 0
Apply the distributive property.<span><span><span><span>3⋅2</span>+<span>3q</span></span>+15</span><span><span><span>3⋅2</span>+<span>3⁢q</span></span>+15</span></span>Multiply <span>33</span> by <span>22</span> to get <span>66</span>.<span><span><span>6+<span>3q</span></span>+15</span><span><span>6+<span>3⁢q</span></span>+15</span></span>Add <span>66</span> and <span>1515</span> to get <span>2121</span>.<span><span>3q</span>+<span>21</span></span>
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I need help pls:) and if u need help just tell me
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2 years ago
Why is point A equal to -0.5?
Serggg [28]
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olga nikolaevna [1]
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4 0
2 years ago
Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn
ohaa [14]

Answer:

Step-by-step explanation:

Total number of antenna is 15

Defective antenna is 3

The functional antenna is 15-3=12.

Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.

So,

We line up the 13 good ones, and see where the bad one will fits in

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.

Then,

There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement

ⁿCr= n!/(n-r)!r!

The number of arrangement is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

14C3=364ways

7 0
3 years ago
lung cancer kills about 3,000 people per day. if 90% of the deaths from luung cancer are attributted to smoking, what is the rat
defon

Answer:

2700!

Step-by-step explanation:

hope that helped <3

5 0
3 years ago
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