I need help fast!!!!

Mathematics

2 answers:

Elena L [17]3 years ago

6 0

3q+21c

q=7

If this helped please give stars and a thanks ^.^ much appreciated!

NNADVOKAT [17]3 years ago

5 0

Apply the distributive property.3⋅2+3q+153⋅2+3⁢q+15Multiply 33 by 22 to get 66.6+3q+156+3⁢q+15Add 66 and 1515 to get 2121.3q+21

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Does -x plus -x result in -x?

11Alexandr11 [23.1K]

It results in -2x because 1+1=2 and its the same with negative numbers

5 0

3 years ago

Rewrite 9cos 4x in terms of cos x.

rosijanka [135]

$\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )
\end{cases}
\\\\\\
cos(4\theta)=8cos^4(\theta )-8cos^2(\theta )+1\\\\
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9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
\\\\\\
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as far as the previous one on the 2tan(3x)

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
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$\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[ \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
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2\left[ \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
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$\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
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4 0

2 years ago

About how many cubes were used to make this figure? A. about 40 B. about 70 C. about 100 D. about 140

natta225 [31]

Answer:

Around 100,i.e. 105

Step-by-step explanation:

In the given cube

Length of the cube = 7 unit cells

Breadth of the cube = 3 unit cells

Height of the cube = 5 unit cells

Therefore the number of unit cubes required to make such big cube is nothing but the volume of the big cube = length*breadth*height

⇒Number of cubes used to make that big cube= 7*5*3

= 105

Hence, option D (around 100) is the correct answer

4 0

2 years ago

The bearing of point Y from point X is 070°.

Shkiper50 [21]

The bearing of point X from point Z is 285°

<h3>Calculating bearings </h3>

From the question, we are to determine the bearing of point X from point Z.

Consider the diagram attached

The bearing of point X from point Z is the measure of the angle from the North of Z in the clockwise direction to the line that goes to X.

That is,

The bearing of point X from point Z = 270° + 15°

The bearing of point X from point Z = 285°

Hence, the bearing of point X from point Z is 285°

Learn more on Calculating bearings here: brainly.com/question/22719608

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