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Maslowich
3 years ago
12

Quadrilateral WILDWILDW, I, L, D is inscribed in circle OOO. \overline{WI} WI start overline, W, I, end overline is a diameter o

f circle OOO. What is the measure of \angle D∠Dangle, D? ^\circ ∘ degrees

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

Question not well presented and diagram is missing

Quadrilateral WILD is inscribed in circle O.

WI is a diameter of circle O.

What is the measure of angle D?

See attached for diagram

Answer:

Step-by-step explanation:

Summation of opposite angles of a quadrilateral inscribed in a circle is 180°, given that the vertices are on the circle.

Given

<WIL = 45°

<ILD = 109°

In the attached;

<WIL + <WDL = 180° (Opposite angle of quadrilateral)

Substitute 45° for <WIL in the above expression

45° + <WDL = 180° ---- Collect like terms

<WDL = 180° - 45°

<WDL = 135°

Hence, the measure of angle D is 135° (See attached)

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Answer:

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Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

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\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

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\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

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Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

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Simplify:

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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We are given;

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