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madam [21]
3 years ago
13

Luis starts to do a division problem and notices that there is a pattern in the digits to the right of the decimal point.

Mathematics
2 answers:
Papessa [141]3 years ago
7 0
<span>(B)rational
if there were no discernible pattern in the digits, then it would be irrational</span>
arsen [322]3 years ago
5 0

Answer:

(A) irrational

Step-by-step explanation:

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Answer:

\frac{x }{2}  = 72.8

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What is the ratio of 4 cm x 72 cm what is the ratio of 6 cm x 48 cm what is the ratio of 8 cm x 36 cm and what is the ratio of 2
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4/72 = 1/18

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816 divided by 2 long division
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In a study, 43% of adults questioned reported that their health was excellent. A researcher wishes to study the health of people
marishachu [46]

Answer:

13.44% probabilith that at most 3 are in excellent health.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they are in excellent health, or they are not. The probability of an adult being in excellent health is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

43% of adults questioned reported that their health was excellent.

This means that p = 0.43

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This means that n = 13

Find the probability that when 13 adults are randomly selected, at most 3 are in excellent health.

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{13,0}.(0.42)^{0}.(0.58)^{13} = 0.0008

P(X = 1) = C_{13,1}.(0.42)^{1}.(0.58)^{12} = 0.0079

P(X = 2) = C_{13,2}.(0.42)^{2}.(0.58)^{11} = 0.0344

P(X = 3) = C_{13,3}.(0.42)^{3}.(0.58)^{10} = 0.0913

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0008 + 0.0079 + 0.0344 + 0.0913 = 0.1344

13.44% probabilith that at most 3 are in excellent health.

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Answer:

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17.(8× + 2)° (4× + 4)°

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