What is the answer to this?

Mathematics

1 answer:

seropon [69]3 years ago

4 0

Answer:

16.66

17.(8× + 2)° (4× + 4)°

Step-by-step explanation:

Hindi ko po alam Kung tama ito pero po Sana makatulong ito

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A triangle has an area of 35 square inches. the length of one of the sides it 10 inches. what is the length of the perimeter? in

Serggg [28]

The perimeter would be about 34.4 because if you choose the bottom side to be ten, by multiplying 35 by 2 to get 70 you can divide by 10 to get 7. Since you know the height and width, you can use pythagorean theorem, a^2 + b^2 = c^2. Plug in the numbers you have 10^2+7^2=c^2. c^2=149, so if you square root 149 you will get a irrational number but when rounded you get 12.2- so that is one side multiply by 2 and get 24.4- and add 10 to get 34.4

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3 years ago

HELP ME WITH MATH ANGLES PLEASE BRAINLIST

mamaluj [8]

the second slide is A. 22

and the last one is x=81 z=99 and y=68

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4 years ago

The ratio of the number of boys to the number of girls in a theater is 7:9. There are 12 more girls than boys. How many children

skelet666 [1.2K]

Ok, there is an equation you can use to solve it.

n is a number.

p is also a number, but different to n.

$\frac { 7 }{ 9 } \cdot \frac { n }{ n } =\frac { p }{ p+12 } \\ \\ \frac { 7 }{ 9 } \cdot 1=\frac { p }{ p+12 } \\ \\ \frac { 7 }{ 9 } =\frac { p }{ p+12 }$

$\\ \\ 7\left( p+12 \right) =9p\\ \\ 7p+84=9p\\ \\ 9p-7p=84\\ \\ 2p=84\\ \\ p=\frac { 84 }{ 2 } \\ \\ p=42$

Therefore:

<u></u> $\frac { 7 }{ 9 } \cdot \frac { n }{ n } =\frac { 42 }{ 42+12 } =\frac { 42 }{ 54 } =\frac { 7 }{ 9 } \cdot \frac { 6 }{ 6 } \\ \\ \therefore \quad n=6$

So all together there were 54 girls and 42 boys in the theatre.

54 + 42 = 96

That's 96 children in total. (Answer)

7:9 = 42:54

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3 years ago

After the last ice age began, the number of animal species in Australia changed rapidly. The relationship between the elapsed ti

Anarel [89]

Answer:

Every decade, the number of species decays by a factor of 0.0834.

Step-by-step explanation:

Let be $S(t) = 25,000,000\cdot 0.78^{t}$ , $\forall t \geq 0$ . The decay rate per decay is deducted from the following relation: