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saw5 [17]
3 years ago
6

Given g(x)=-x-2, find g(1)

Mathematics
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

G(x)=−12x2−2x

Step-by-step explanation:

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If f(x)= 3x2- 2x + 3 then find what f(3) is equal to
Anettt [7]

Answer:

Answer is 24

Step-by-step explanation:

given \: f(x) = 3 {x}^{2}  - 2x + 3 \\ to \: find \: f(3) \ : \:  ? \\ f(3) = 3( {3}^{2} ) - 2(3) + 3    \\ = 3(9) - 6 +3 \\  = 27 - 3 \\  = 24

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.

5 0
2 years ago
Read 2 more answers
ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?
MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = \sqrt{(x_2-x_1)^2 +( y_2-y_1)^2

Step 1: Finding the length of  EF

By using distance formula,

EF = \sqrt{(-7 - 0)^2 + (4-0)^2}

EF = \sqrt{(49) + (16)}

EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\

Step 2: Finding the length of  FG

By using distance formula,

FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}

Step 2: Finding the length of  GE

GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8

Thus we could see that the sides EF = FG

So it is  a isosceles triangle.

6 0
2 years ago
Solve the following system of equations by the substitution method.
Dahasolnce [82]

Answer:

Step-by-step explanation:

5x=y+6   --------- equ 1

2x-3y=4  -------- equ 2

5x - 6 = y

y = 5x - 6

substitute in equ 2

2x-3(5x - 6) =4

2x - 3*5x + 3*6 = 4

2x - 15x + 18 = 4

- 13x = 4 - 18

-13x = -14

x = -14/-13

x = 14/13

substitute  in equ 1

5*14/13 = y+6  

70/13 - 6 = y

y =  ( 70 - 78)/13

y = -8/13

6 0
2 years ago
Construction worker’s planned to secure a tall pole using two cables attached to the pole at a point 12 m above the ground as sh
padilas [110]

Answer:(24+12\3)m

Step-by-step explanation:

6 0
2 years ago
The decay constant of a radioactive element is -0.533 per minute. If a sample of the element weighs 50 grams, what will be its w
Stels [109]
y=50e^{-0.533\times2}\approx17.2192\text{ g}
7 0
3 years ago
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