(a) Net present value of machine
Pm=-C+V/(1+i)^n=37000-1000/1.08^4
=-36264.97
=-36265 (rounded to nearest dollar)
Cost of machine amortized over 4 years (annualized cost)
Ac=Pm(A/P,i,n)=-36264.97(A/P,0.08,4)=-36264.97(.08*(1.08^4)/(1.08^4-1)
=-10949.15
Expected year-end cash flow = annualized return - annualized cost =>
12000=return - 10949.15
(b) Internal rate of return of machine
=return/cost - 1
=(12000-(-10949.15)/10949.15-1
=2.096-1
=1.096
=109.6%
Answer:
Step-by-step explanation:
Let A1 be the area of one square and A2 be the area of second square
So,
A1 = s^2
where s is side of square
So side of one square is 
To calculate the length of fence we need to find the perimeter of the square
So,
P1 = 4 * s
For second square:
The perimeter will be:
So the total fence will be: P1+P2
Answer:
x = 45/17
Step-by-step explanation:
We can move all x to 1 side and all the numbers to another. You can add 8.7 on both sides and get that 2.3x = 0.8x + 4.5. Next, we subtract by 0.8x on both sides to get that 1.7x = 4.5, where we can then divide by 17/10 on both sides to get that x is equal to 45/10 * 10/17, so that means that x = 45/17.
Answer:
4:1, 6:2, 12:3, 24:6
Step-by-step explanation:
24 boy
6 girls
possible ratio
24 ÷ 6 = 4
6÷ 6 = 1
4 : 1
24 ÷ 3 = 6
6 ÷ 3 = 2
6 : 2
24 ÷ 2 = 12
6 ÷ 2 = 3
12 : 3
24 ÷ 1 = 24
6 ÷ 1 = 6
24 :6
We know that
<span>Out of 120 students----------> 34 chose orange as the favorite fruit
</span>Find the <span>percentage
</span><span>percentage=34/120------> 17/60-----> 0.2833------> 28.33%
for </span>2,000 students
0.2833*2000=566.67-----------> about 567 students
the answer is
about 567 students
