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3 years ago

7

HELP PLEASE

2 answers:

Gnesinka [82]3 years ago

7 0

Answer: $x^2=8y$

Step-by-step explanation:

Let the given parabolic mirror opens upwards and vertex=(0,0)

Focus point of the parabolic mirror is located 2 inches from the vertex of the mirror. ∴ p=2

Since, the parabola opens upward, then the equation of the parabola is of the form $x^2=4py$

Substitute the value of p=2 in this, we get the equation of the parabolic mirror

$x^2=4(2)y\\\Rightarrow\ x^2=8y$

Hence, the equation of the parabola that models the cross section of the mirror is $x^2=8y$

faust18 [17]3 years ago

5 0

An equation of the parabola that models the cross section of the mirror is y = 1/8 × x² I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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The Empire State Building weighs about 7.3×108pounds. The One World Trade Center building weighs about 88,200,000 pounds. What i

In-s [12.5K]

Answer:

$8.182X10^8 $pounds$

a=8.182 and b=8

Step-by-step explanation:

Weight of the Empire State Building = $7.3X 10^8$ pounds.

Weight of the One World Trade Center building= 88,200,000 pounds.

= $8.82 X 10^7$

The addition of the two:

$=7.3X 10^8+8.82 X 10^7\\$To make it easier to add, express both as powers of 8\\=7.3X 10^8+0.882 X 10^8\\=(7.3+0.882)X10^8\\=8.182X10^8 $ pounds$

Comparing with the form: $aX10^b$

a=8.182 and b=8

4 0

3 years ago

The ratio of incorrect to correct answers on Marco's math test was 4 to 6. If Marco missed 39 problems, how many did he get corr

lesantik [10]

39/6= 6.5 then u multiply
6.5 times 4 = 26
which 26 is your answer

3 0

3 years ago

Given the linear programming problem, use the method of corners to determine where the minimum occurs and give the minimum value

algol [13]

Answer:

Minimum value of function $C=x+10y$ is 63 occurs at point (3,6).

Step-by-step explanation:

To minimize :

$C=x+10y$

Subject to constraints:

$x\leq 3---(1)\\y\leq 9---(2)\\x+y\geq 9----(3)\\x\geq 0\\y\geq 0$

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line

Eq (2) is in green in figure attached and region satisfying (2) is below the green line

Considering $x+y\geq 9$ , corresponding coordinates point to draw line are (0,9) and (9,0).

Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line

Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)

Now calculate the value of function to be minimized at each of these points.

$C=x+10y$

at A(0,9)

$C=0+10(9)\\C=90$

at B(3,9)

$C=3+10(9)\\C=93$

at C(3,6)

$C=3+10(6)\\C=63$

Minimum value of function $C=x+10y$ is 63 occurs at point C (3,6).

3 0

3 years ago

Which function will have the steepest graph? O y=-2x O y=-* Oy = 3 x 2 2 Oy=

Alenkinab [10]

Step-by-step explanation:

can I have actual options I can't figure it out with invalid options

3 0

3 years ago

Read 2 more answers

Find the value of x.<br> 31.7, 42.8, 26.4, x, mean 35

Troyanec [42]

Answer:

x = 39.1

Step-by-step explanation:

mean = average off all the numbers =

sum of the numbers / amount of numbers.

35 = sum of the #'s / # of #'s

35 = 100.9 + x / 4

35 × 4 = 100.9 + x / 4 × 4

140 = 100.9 + x

140 – 100.9 = 100.9 + x – 100.9

39.1 = x

x = 39.1

6 0

2 years ago