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AURORKA [14]
3 years ago
9

My speaker on my phone is not working, when I try and play music and videos the sound dosen't work. However my alarm works. Can

someone help me?
Computers and Technology
2 answers:
Leni [432]3 years ago
8 0

Answer:

Try factory resetting

SVEN [57.7K]3 years ago
7 0
Try turning off your phone or resetting it
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Which of the following was not important in the development of the internet?
lesantik [10]
D. Rise of NASA.Hope I helped.
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NEED HELP ON TEST!!!
Phoenix [80]

Answer:

1.  \: speaker \:  notes \\ 2. \: accessible

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3 years ago
This function receives first_name and last_name, then prints a formatted string of "Name: last_name, first_name" if both names a
pishuonlain [190]

Answer:

Following are the program in the C++ Programming Language.

//set header file

#include <iostream>

//set namespace

using namespace std;

//define class

class format

{

//set access modifier

public:

//set string type variable

 string res;

//define function

 void names(string first_name, string last_name)

 {  

//set if-else if condition to check following conditions

   if(first_name.length()>0 && last_name.length()>0)

   {

     res="Name: "+last_name+", "+first_name;

   }

   else if(first_name.length()>0 and last_name.length()==0)

   {

     res="Name: "+first_name;

   }

   else if(first_name.length()==0 and last_name.length()==0)

   {

     res="";

   }

 }

//define function to print result

 void out(){

   cout<<res<<endl;

 }

};

//define main method

int main() {

//set objects of the class

 format ob,ob1,ob2;

//call functions through 1st object

 ob.names("John","Morris");

 ob.out();

//call functions through 2nd object

 ob1.names("Jhon","");

 ob1.out();

//call functions through 3rd object

 ob2.names("", "");

 ob2.out();

}

<u>Output</u>:

Name: Morris, John

Name: Jhon

Explanation:

<u>Following are the description of the program</u>:

  • Define class "format" and inside the class we define two void data type function.
  1. Define void data type function "names()" and pass two string data type arguments in its parameter "first_name" and "last_name" then, set the if-else conditional statement to check that if the variable 'first_name' is greater than 0 and 'last_name' is also greater than 0 then, the string "Name" and the following variables added to the variable "res". Then, set else if to check that if the variable 'first_name' is greater than 0 and 'last_name' is equal to 0 then, the string "Name" and the following variable "first_name" added to the variable "res".
  2. Define void data type function "out()" to print the results of the variable "res".
  • Finally, we define main method to pass values and call that functions.
3 0
3 years ago
There are 2048bytes in4megabytes true or false​
ollegr [7]

Answer:

Explanation:

bonjour,

1 MB =  1 000 000 B (bytes)

4 MB = 4 000 000B

=> false

5 0
2 years ago
In order to "print" the data in an object, the class should override the _____ method.
Olegator [25]

Answer:

toString is right Answer

Explanation:

If you want to represent any object as a string, toString() method comes into existence.  

The toString() method returns the string representation of the object.

If you print any object, java compiler internally invokes the toString() method on the object. So overriding the toString() method, returns the desired output, it can be the state of an object etc. depends on your implementation.

7 0
3 years ago
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