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gtnhenbr [62]
4 years ago
12

In calculating the concentration of [Cu(NH3)4]2+[Cu(NH3)4]2+ from [Cu(H2O)4]2+[Cu(H2O)4]2+, the stepwise formation constants are

as follows: K1=1.90×104K1=1.90×104 K2=3.90×103K2=3.90×103 K3=1.00×103K3=1.00×103 K4=1.50×102K4=1.50×102 Calculate the overall formation constant (KfKf) for the formation of [Cu(NH3)4]2+[Cu(NH3)4]2+ from [Cu(H2O)4]2+[Cu(H2O)4]2+ .
Chemistry
1 answer:
tamaranim1 [39]4 years ago
3 0

Answer:

11.1×10^12

Explanation:

β4= K1× K2 × K3 × K4

β4= 1.90×10^4 × 3.90×10^3 × 1.00×10^3 ×1.50×102

β4=11.1×10^12

The overall formation (stability) constant β4= K1× K2 × K3 × K4. Hence the answer.

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abruzzese [7]

Answer:

The heat of formation of SO2 is -296.1 kJ

Explanation:

<u>Step 1:</u> Data given

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<u>Step 2</u>: Calculate the heat of formation of SO2

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2SO2 (g)+O2 (g)→2SO3 (g)  ΔH = -198.2 kJ

SO3(g) → SO2(g) + 1/2 O2(g)   ΔH = 99.1 kJ

----------------------------------------------------------------

S(s) + 3/2 O2(g) → SO3(g)    ΔH = -395.2 kJ

SO3(g) → SO2(g) + 1/2 O2(g)   ΔH = 99.1 kJ

-------------------------------------------------------------------

S (s)+O2 (g)→SO2 (g)

ΔHrxn = (-790.4 /2) kJ + (198.2/2) kJ

ΔHrxn = -395.2 kJ + 99.1 kJ = 296.1 kJ

The heat of formation of SO2 is -296.1 kJ

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Answer:

Hello

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