Answer: 1. b
2. c
3. a
Explanation: A chemical reaction in equilibrium is actually in a dynamic euqilibrium, which means that changing a condition will make the equilibrium move to counteract the action and reestate the equilibrium.
For example, in the reaction:
N2(g) + 3H2(g) ⇄ 2NH3(g)
1. <u>Adding H2</u>: if you add the reagent, to reestate the equilibrium, the reaction will produce more products so, it will <u>move to the right</u>;
2. A <u>catalyst</u> doesn't interfere in the equilibrium, because it moves to the right and to the left at the same extent. Therefore, there is <u>no effect</u>.
3. <u>Decrease the pressure</u>: when you decrease the pressure of a reaction, the equilibrium will make the pressure increase again by moving towards the side of the reaction which has more molecules, so, it <u>shifts to the left</u>;
Answer:
They are in same group/family.
Explanation:
Alkaline earth metals are present in group 2 of periodic table. There are six elements in second group. Beryllium, magnesium, calcium, strontium, barium and radium.
All have two valance electrons but in different energy levels. Thus they have similar chemical properties.
Electronic configuration of calcium.
Ca = [Ar] 4s²
Electronic configuration of strontium.
Sr = [Kr] 5s²
They are present in group two and have same number of valance electrons (two valance electrons) and show oxidation state +2 by loosing two valance electrons. They also show similar reactivity.
They react with oxygen and form oxide.
2Sr + O₂ → 2SrO
2Ca + O₂ → 2CaO
this oxide form hydroxide when react with water,
SrO + H₂O → Sr(OH)₂
CaO + H₂O → Ca(OH)₂
With sulfur,
Sr + S → SrS
Ca + S → CaS
I think it’s C but I’m not sure
The problem ask to show the reaction between the two elements which is calcium and oxygen to form an ionic compound. Base on the data that Calcium has n electronic compound of 2.8.8.2 and oxygen has 2.6, the reaction of the both is to add 2 electron in Calcium and also in the oxygen because both of the m has 2 extra electron
