Answer:
General admissions sold: 880
Reserved seating sold: 256
Step-by-step explanation:
Set up equation:
Variable x = people who bought general admission
Variable y = people who bought reserved seating
x + y = 1136
5x + 7y = 6192
Isolate a variable in any equation:
Y = 1136 - x
Substitute the value of the variable in the other equation:
5x + 7(1136 - x) = 6192
5x + 7952 - 7x = 6192
-2x + 7952 = 6192
-2x = -1760
x = 880
Substitute the value of x in any equation:
880 + y = 1136
y = 256
Check your work:
880 + 256 = 1136
1136 = 1136
Correct!
5(880) + 7(256) = 6192
4400 + 1792 = 6192
6192 = 6192
Correct!
Answer:
z=70
Step-by-step explanation:
Cross multiply to make it 5z=350, solve for z=70
<h3>
Answer: 1010</h3>
If your teacher asked you to round to 4 sig figs, then you'd simply say 1005. But your teacher wants 3 sig figs, which means we'll have to round 1005 to some number where that last '5' is a '0'. The rule is trailing zeros, or zeros on the right, are not significant.
For example, the numbers 5700 and 5,700,000 both have the same number of sig figs. Basically they are 57 and then tack on some number of zeros.
Reading the number from left to right has us see 100 as the first three digits. The last digit is 5, which means we round the second to last digit (0) up by 1 going from 100 to 101. Then we replace the 5 with 0.
So 1005 turns into 1010. One way to think of it is to say to yourself "I need to round 1005 to the nearest ten, so I'll go to 1010". You could argue that since 5 is exactly half way between 0 and 10, you could go either direction. Convention usually dictates you round up. I like to think of shopkeepers who round up to make sure they don't lose money when it comes to rounding transaction fees.
With 1010, the first zero is significant while the second zero is not. Therefore the placement of zeros is important. As long as a zero is between two nonzero elements, then that zero is significant.
I think it’s not equal because if you took (1)(2)(3). You would need to multiply them not add them. It would be 9 = (1,2,3)
Answer:
when they are far away from each other they will move at a velocity of v∞/q = 1.84*10⁶ m/(s*C)
Step-by-step explanation:
if we assume that the charges repel according to a Coulomb's law ( we neglect any relativistic effects) , then the force of repulsion is
F rep = k*q*q/r²
where q= charge
k= Coulomb's constant
r= distance
from Newton's second law :
F rep = m*a= m*dv/dt = m*dv/dr * dr/dt = m*v*dv/dr
k*q*q/r² = m*v*dv/dr
k*q*q/(m*r²) = v*dv/dr
(k*q*q/m) ∫ r⁻² dr= ∫v*dv
-2*k*q*q/m*r = v² - v₁²
for r=r₀ , v=0 ,then
-2*k*q*q/m*r₀ = 0 - v₁²
v₁² = 2*k*q*q/m*r₀
v²= -k*q*q/(m*r) + v₁²= 2*k*q*q/m* (1/r₀-1/r)
then
v²= 2*k*q²/m* (1/r₀-1/r)
when the masses are far away from each other r→∞ , 1/r → 0, then
v∞² = 2*k*q²/(m*r₀)
v∞ = √[2*k*q²/(m*r₀)]
since
k= 8.987*10⁹ N·m²/C² , m= 1 mg = 0.001 kg , r₀= 5.3 cm = 0.053 m
v∞/q = √[[2*k/(m*r₀)] = √[2*8.987*10⁹ N·m²/C²/(0.001 kg*0.053 m)] = 1.84*10⁶ m/(s*C)
v∞/q = 1.84*10⁶ m/(s*C)