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2 years ago

Solve equation for the given variable

Mathematics

2 answers:

Alenkinab [10]2 years ago

8 0

Answer:

p=30

Step-by-step explanation:

First, you need to subtract 10 from both sides to get 1/2p=25. You do this just because simplifying is much easier.

Then, you need to isolate p, so you divide 1/2 by both sides, which is the same thing as multiplying by 2. 1/2*2p=15*2.

Simplifying, you get p=30.

saul85 [17]2 years ago

8 0

Answer:

2. x = 2

3. p = 30

4. n = 1/10 ---> less than 1 whole

5. r = 5/2 ----> greater than 1 whole

Step-by-step explanation:

See the images attached below for better understanding. If you don't understand the steps I've composed, please comment down below and I will help you! :)

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Answer:

Step-by-step explanation:

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3 years ago

Find the product.

IrinaK [193]

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4 0

3 years ago

Where y=5x-7 and -3x-2y=-12 Write your answer as x,y

Mariulka [41]

Answer:

(x,y) = (2,3)

Step-by-step explanation:

y=5x-7 (i)

-3x-2y= -12

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By putting the value of y from (i) in (ii)

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2 years ago

segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc

Elan Coil [88]

Answer:

The magnetic field is $B = 3.87 *10^{-6} \ T$

Direction is inward

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The radius of BC is $r_{BC} = 30 \ cm = 0.30 \ m$

The radius of DA is $r _{DA} = 20 \ cm = 0.20 \ m$

The length of CD is $r_{CD} = 10 cm = 0.1 \ m$

The length of AB is $r_{AB} = 10 cm = 0.1 \ m$

The current is $I = 11.4A$

The magnetic field is mathematically represented as

$B = B_{BC} + B_{DA} + B_{CD} + B_{AB}$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]$

Where

$\theta_{BC} = \theta_{DA} = \frac{2\pi}{3}$

Where $\frac{2 \pi}{3} = 120^o$

$\theta_{CD} = \theta_{AB} = 0^o$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]$

$B = 3.87 *10^{-6} \ T$

The direction is into the page

This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule the direction of current is perpendicular to the direction of magnetic field so since current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0

3 years ago