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3 years ago

15

I need help please ASAP

1 answer:

storchak [24]3 years ago

8 0

Answer:

8.80

hope this helps :)

Step-by-step explanation:

since it is 3% you have to divide it by 3,408

[3%]/[3,408]= 8.80

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A new car is purchased for 16400 dollars. The value of the car depreciates at 8.25% per year. What will the value of the car be,

PolarNik [594]

16400*0.0825= 1353

1353*10= 13530

16400-13530= $2870

8 0

3 years ago

Read 2 more answers

Pls helpppp!!! I will give brainliest.

pashok25 [27]

Answer:

Step-by-step explanation:

The domain represents the x-values

The range represents the y-values

Domain Range

3 7

8

-2

4

1

This relation is not a function because the domain value was used more than one time.

8 0

3 years ago

Find two numbers witha sum of 20 and a difference of 14

bixtya [17]

from the given equation

X+Y=20-->i

X-Y=14--->ii

add eq i and eq ii

2x=34

x=17

putting the value of x=17 in eq i

17+y=20

then y = 3 so the right answer is

17 and 3

6 0

3 years ago

Nick will move a storage bin from its current location to the new location shown on the coordinate plane. Describe how Nick coul

nlexa [21]

Answer:

Move downward by 7 units

Move leftward by 6 units

$(x,y) \to (x -6,y-7)$

Step-by-step explanation:

Given

See attachment for grid

Required

The transformation from the current location to the new location

To do this, we pick two corresponding points on the current location and the new location.

We have:

$A = (3,2)$ -- Current location

$A' = (-6,-5)$ -- New location

First, move A downwards by 7 units.

The rule to this is:

$(x,y) \to (x,y-7)$

So, we have:

$(3,2) \to (3,2-7)$

$(3,2) \to (3,-5)$

Next, move the above points leftward by 6 units.

The rule to this is:

$(x,y) \to (x-6,y)$

So, we have:

$(3,-5) \to (3-6,-5)$

$(3,-5) \to (-3,-5)$

6 0

3 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago