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3 years ago

15

Using the matrix solver on your calculator, find the solution to the system of

1 answer:

OleMash [197]3 years ago

7 0

The answer is answer choice D)

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How do you rearrange the equation (2x) /(4pi) +((1-x) /2) =0 to solve for x?

USPshnik [31]

$\frac{2x}{4 \pi } + \frac{1-x}{2} =0 \\ 
 \frac{x}{2 \pi } + \frac{1-x}{2} = 0$
Then we will multiply both sides of the equation by 2 π :
x + π ( 1 - x ) = 0
x + π - π x = 0
x ( 1 - π ) = - π / · ( - 1 )
x ( π - 1 ) = π
x = π / ( π - 1 )

3 0

3 years ago

Write out the form of the partial fraction decomposition of the function (as in this example). do not determine the numerical va

neonofarm [45]

$\frac{x^{4}-2x^{3}+x^{2}+7x-5}{x^{2}-2x+1} = x^{2}+\frac{a}{x-1}+\frac{b}{(x-1)^{2}}$
It looks like your first selection (a) is appropriate.

7 0

3 years ago

−4 = 2t − 2 what does t equal

sladkih [1.3K]

Answer:

t = -1

Step-by-step explanation:

-4 = 2t - 2

2t = -2

t = -1

Can I get brainliest

8 0

3 years ago

Read 2 more answers

Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v

Juliette [100K]

Compute the surface element:

$\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}$

$\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}$

So the integral is

$\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)$

$=\dfrac23(37^{3/2}-1)$

4 0

3 years ago

You attend a baseball game with friends and visit the snack stand between innings. Soda costs $2 a can, and a box of popcorn cos

horsena [70]

Answer:

I feel that is would be D

Step-by-step explanation:

This is the most reasonable awnser.

8 0

2 years ago