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Vikentia [17]
2 years ago
15

Dean has $70 in a savings account that earns 5% interest, compounded annually. To the nearest cent, how much will he have in 3 y

ears?
Mathematics
1 answer:
SSSSS [86.1K]2 years ago
8 0

Answer:

lmjtntndadwtwpwpwpmpmwpmpmq

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Don deposited $3,500 for 5 years on 2.40 pa interest rate in his savings account how much simple interest will he earn
Feliz [49]
3,500 (.024) = 84
84 (5) = $420 in simple interest
5 0
3 years ago
My hw says, "suppose E has a coordinate of -1 And EG= 7" what is the possible coordinate of G?​
evablogger [386]

Answer:

-8,6

Step-by-step explanation:

from what i can tell this is a 1D problem. |E-G|=7, and E=-1, so -1-G=+-7. G=-8 or 6

7 0
2 years ago
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I need help in this . Just ignore that equation in top of the problem
GuDViN [60]
Communtative property
5 0
3 years ago
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The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?
omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

T_5 = 160

T_7 = 40

Required

T_6

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

\frac{T_7}{T_5} = \frac{40}{160}

Divide the numerator and the denominator of the fraction by 40

\frac{T_7}{T_5} = \frac{1}{4} ----- equation 1

Recall that the formula of a GP is

T_n = a r^{n-1}

Where n is the nth term

So,

T_7 = a r^{6}

T_5 = a r^{4}

Substitute the above expression in equation 1

\frac{T_7}{T_5} = \frac{1}{4}  becomes

\frac{ar^6}{ar^4} = \frac{1}{4}

r^2 = \frac{1}{4}

Square root both sides

r = \sqrt{\frac{1}{4}}

r = ±\frac{1}{2}

Next, is to solve for the first term;

Using T_5 = a r^{4}

By substituting 160 for T5 and ±\frac{1}{2} for r;

We get

160 = a \frac{1}{2}^{4}

160 = a \frac{1}{16}

Multiply through by 16

16 * 160 = a \frac{1}{16} * 16

16 * 160 = a

2560 = a

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

T_n = a r^{n-1}

Here, n = 6;

T_6 = a r^{6-1}

T_6 = a r^5

T_6 = 2560 r^5

r = ±\frac{1}{2}

So,

T_6 = 2560( \frac{1}{2}^5) or T_6 = 2560( \frac{-1}{2}^5)

T_6 = 2560( \frac{1}{32}) or T_6 = 2560( \frac{-1}{32})

T_6 = 80 or T_6 = -80

T_6 =±80

Hence, the 6th term is positive/negative 80

8 0
2 years ago
Identify the median and IQR of the data set below.20222426283032Your answerWhich dota
Dennis_Churaev [7]

We are given a boxplot that contains some data. We will use the information below to analyze the given question.

STEP 1: Median

From the image above, we can see that the median represents the line drawn inside the box

This gives;

\text{Median}=24

STEP 2: Interquartile range

The interquartile range is the difference between the third quartile and the first quartile.

\begin{gathered} q_3=28 \\ q_1=22 \\ \text{IQR}=28-22 \\ \text{IQR}=6 \end{gathered}

4 0
1 year ago
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