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3 years ago

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Carlos can read 30 pages per hour in the 270-page book that he is reading. at this rate, how long will it take him to finish the

book?

1 answer:

devlian [24]3 years ago

8 0

I hope this helps you

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which answer choice explains the pattern for how to find the slope using an equation in standard form?

Liono4ka [1.6K]

Question is using standard formula ax+by=c to find the slope by converting into slope intercept form y=mx+b

so we also need to convert ax+by=c into y=mx+b as shown below:

$ax+by=c$

$ax+by-ax=c-ax$

$by=-ax+c$

divide both sides by

$y=-\frac{a}{b}x+\frac{c}{b}$

Now compare it with y=mx+b, we get

$m=-\frac{a}{b}$

So using values of a and b, we can find the slope

compare given equation -5x+2y=15 with ax+by=c, we get:

a=-5, b=2

Now plug both into above formula

$m=-\frac{a}{b}$

$m=-\frac{-5}{2}$

$m=\frac{5}{2}$

Now matching these details with given choices we find that THIRD choice is the final answer.

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3 years ago

Why does the shape of the distribution of the weights of russet potatoes tend to be symmetrical?

Sergio [31]

Answer:

Mean ≈ Median

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3 years ago

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

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3 years ago

Please please help me on this

Goryan [66]

Answer:

a

Step-by-step explanation:

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3 years ago

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PLEASE HELP!! I'll make brainliest

Gekata [30.6K]

Sorry people send you links instead of actually helping you

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3 years ago