Question

Dan has five times as many $1 bills has $5 bills. He has a total of 48 bills. Define a variable and write an equation to solve for how many $5 bills he has. How much money does he have in total?
PLEASE show an explanation.

Answer 1

Answer:

Part 1) Dan has 8 bills of $5 and 40 bills of $1

Part 2) The total money that Dan has is $80

Step-by-step explanation:

Let

x -----> the number of $1 bills

y ----> the number of $5 bills

we know that

$x+y=48$ -----> equation A

$x=5y$ -----> equation B

Solve the system by substitution method

substitute equation B in equation A and solve for y

$5y+y=48$

$6y=48$

$y=8$

Find the value of x

$x=5y$

$x=5(8)=40$

The total money that Dan has is

$40(1)+8(5)=\ 80$

therefore

Dan has 8 bills of $5 and 40 bills of $1

The total money that Dan has is $80