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shusha [124]
3 years ago
6

Attention!!:Will give brainliest, plz put the right answer. 1.Tim wrote 16 as(-2)^4. Is he correct? Explain. 2.Could −2 be used

as a base to rewrite 32? 64? Why or why not?
Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

Hey there!

Tim is correct. (-2)^4=-2(-2)(-2)(-2), which is 16.

-2 can be used as a base, because (-2)^5=32, and (-2)^6=64

Let me know if this helps :)

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GarryVolchara [31]

Answer:

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Step-by-step explanation:

3 0
3 years ago
I need help on these problems
Mazyrski [523]
Hope this helps and hope you can read it, if not let me know :)

4 0
4 years ago
Help need badly please
inna [77]

Answer:

6

Step-by-step explanation:

subtract 2 from2 equal zero

add 2and 4 together get six

zero divided by any non-zero number gives zero

multiply 3 times 4 gets 12

0+12/2

divide 12 by 2 equal six

0+6

zero 0 and 6 to get 6

6

7 0
3 years ago
Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.
bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Substitute sin(\theta)=\frac{6}{11} into the first equation, solve for the cosine and simplify. Then, you obtain:

cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}

As sec\theta then cos\theta:

cos(\theta)=-\frac{\sqrt{85}}{11}

Now we can find tan\theta:

tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}

4 0
3 years ago
Read 2 more answers
What is the area of the figure below?<br> 6 in.<br> 5 in.<br> 4 in.
uysha [10]
120
6x5x4=120
hope this helps
4 0
3 years ago
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