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3 years ago

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1 answer:

Valentin [98]3 years ago

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There was 645 womens at first

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A floor is made up of 20 triangular tiles, each with sides 40 cm, 24 cm and 32 cm. Find the cost of polishing the floor at the r

pochemuha

Answer:

$15360\,\,rupees$

Step-by-step explanation:

Let sides of the triangle be $a,b,c$

$a=40\,,\,b=24\,,\,c=32$

Semi-perimeter (s) = $\frac{a+b+c}{2}$

$=\frac{40+24+32}{2}\\ =\frac{96}{2}\\=48$

Area of one tile $=\sqrt{s(s-a)(s-b)(s-c)}$

$=\sqrt{48(48-40)(48-24)(48-32)}\\ =\sqrt{48(8)(24)(16)}\\ =\sqrt{147456} \\=384\,\,cm^2$

So,

Area of 20 tiles $=20(384)=7680\,\,cm^2$

Cost of polishing the floor at the rate of 2 rupees per sq.cm = $7680(2)=15360\,\,rupees$

7 0

3 years ago

Help me plzzzzzzzzzzzzz

andreyandreev [35.5K]

Answer:

Q1.

a. three hundred sixty-four thousand eight hundred twenty-five

b. one hundred forty-three

c. nine hundred four thousand three hundred six

d. seven million twenty

e. fifty-six million thirty thousand one hundred twenty-three

f. six thousand twenty-four

g. two hundred four

h. six hundred seventy-four thousand one

i. nine hundred sixty-two thousand three hundred forty-two

Q2.

a. 5000000

b. 1000004

c. 60000203

d. 1311

e. 286

f. 34503271

g. 844536

h. 3748

i. 125064

j. 4605231

5 0

3 years ago

7. Are the ordered pairs below an arithmetic sequence or geometric

DochEvi [55]

Answer:

8. Arithmetic Progression

9. $f(9) = 300$

Step-by-step explanation:

Given

$\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}$

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

$d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3$

This gives:

$d = 45 - 55 = 35 - 45 = 25 - 35$

$d = -10 = -10 = -10$

$d=-10$

<em>Because the common difference is equal, then it is an arithmetic progression</em>

<em></em>

Solving (8):

$f(n) = f(1) + f(n-1)$

To find f(9), we substitute 9 for n

$f(9) = f(1) + f(9-1)$

$f(9) = f(1) + f(8)$

We need to solve for f(8); substitute 8 for n

$f(8) = f(1) + f(8 - 1)$

$f(8) = f(1) + f(7)$

We need to solve for f(7); substitute 7 for n

$f(7) = f(1) + f(7 - 1)$

$f(7) = f(1) + f(6)$

We need to solve for f(6); substitute 6 for n

$f(6) = f(1) + f(6 - 1)$

$f(6) = f(1) + f(5)$

We need to solve for f(5); substitute 6 for n

$f(5) = f(1) + f(5 - 1)$

$f(5) = f(1) + f(4)$

From the function, f(4) = 25 and f(1) = 55.

So:

$f(5)=55 + 25$

$f(5)=80$

$f(6) = f(1) + f(5)$

$f(6) = 55 + 80$

$f(6) = 135$

$f(7) = f(1) + f(6)$

$f(7) = 55 + 135$

$f(7) = 190$

$f(8) = f(1) + f(7)$

$f(8) = 55 + 190$

$f(8) = 245$

$f(9) = f(1) + f(8)$

$f(9) = 55 + 245$

$f(9) = 300$

8 0

3 years ago

On a coordinate plane, solid circles appear at the following points: (negative 4, 2), (negative 2, 2), (negative 1, 4), (1, 1),

sergeinik [125]

Answer:

A

Step-by-step explanation:

6 0

3 years ago

Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. In the first part of the race, her av

s344n2d4d5 [400]

Nikita's distance from her for the second part of the race was 1.5 kilometers.

Since Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand, and in the first part of the race, her average speed was 8.75 kilometers per hour, while for the second part of the race, she started to get tired, so her average speed dropped to 6 kilometers per hour, to determine which expression represents Nikita's distance for the second part of the race the following calculation must be performed:

8.75 x 0.65 + 6 x 0 = 5.68
8.75 x 0.50 + 6 x 0.15 = 5.275
8.75 x 0.40 + 6 x 0.25 = 5
100 = 60
40 = X
40 x 60/100 = X
24 = X
39 - 24 = 15
15 = 1/4 hour
6/4 = 1.5

Therefore, Nikita's distance from her for the second part of the race was 1.5 kilometers.

Learn more about maths in brainly.com/question/22791791

6 0

2 years ago