Based on the task content given; the initial fee and the fee per stop is $2 and $1.5 respectively.
<h3>Equation</h3>
let
- Initial fee = x
- Fee per stop = y
x + 3y = 6.50
x + 7y = 12.50
- Subtract both equation to eliminate x
7y - 3y = 12.50 - 6.50
4y = 6
y = 6/4
y = 1.5
x + 3y = 6.50
x + 3(1.5) = 6.50
x + 4.5 = 6.50
x = 6.50 - 4.5
x = 2
Therefore, the initial fee and the fee per stop is $2 and $1.5 respectively.
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Answer:
Denote the center of circle as O, the 2 endpoints of shaded segment as AB, then we have:
section OAB area = pi x radius^2 x (120/360) = pi x 6^2 x (1/3) = 37.7 (cm2)
Considering triangle OAB, we have OA = OB = radius, angle AOB = 120 deg. Denote OH as the height of triangle. H lies on AB.
=> Applying cosine and sine theorem in right triangle AHO:
OH = OA x cos 60 = 6 x (1/2) = 3 (cm)
AH = OA x sin 60 = 6 x (sqrt3)/2 = 5.2 (cm)
=> triangle AOB area:
A = triangle AOH area x 2
= AH x OH x (1/2) x 2 = 3 x 5.2 x (1/2) x 2 = 15.6 (cm2)
=> shaded segment area = section OAB area - triangle AOB
= 37.7 - 15.6 = ~21.1 (cm2)
Hope this helps!
:)
Answer:
EFB
Step-by-step explanation:
E,F and B I believe
Answer:
i m not sure Abt the answer bt .... I think the ans is 6 block
