Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
Answer:
The intensity of the first earthquake is 6.31 times the second one
Step-by-step explanation:
The given formulae is M=log(
)
Here for both the earthquakes the value of S is same.
Let the Intensity of the first earthquake be I1 and the second be I2.
Given M1=7.5
M2=6.7
Now M1=log(
)------1
M2=log(
)-----2
Now subtract 1 and 2 we get
M1-M2=log(
)
I1/I2=
I1=I2(
I1=I2*6.31
Answer:
$5
Step-by-step explanation:
If John loses $50 over 10 days, just divide 50 by ten.
