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3 years ago

Find the value of the variable if P is between J & K. JP = 2x ; PK = 7x ; JK = 27

1 answer:

7 0

J ---- P --- K

JP = 2x
PK = 7x
JK = 27

2x + 7x = 27
9x = 27
x = 27/9
x = 3

The value of P is 3.

JP = 2x = 2(3) = 6
PK = 7x = 7(3) = 21

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3 years ago

Can some explain how to do this.

KatRina [158]

We can simplify the expression by using exponent properties, and we will see that the correct option is the fourth option.

<h3>How to simplify the expression?</h3>

Remember the exponent property:

$\frac{a^n}{a^m} = a^{n - m}$

Here we have the expression:

$\frac{83.9*10^{12}*2.87*10^{-3}}{3.76*10^2}$

We can reorder this to get:

$\frac{83.9*10^{12}*2.87*10^{-3}}{3.76*10^2} = \frac{83.9*2.87}{3.76}*\frac{10^{12}*10^{-3}}{10^2}$

The right side can be simplified to:

$\frac{83.9*2.87}{3.76}*\frac{10^{12}*10^{-3}}{10^2} = 64.04*10{12 - 3 - 2} = 64.04*10^{7}$

Now, we can move the decimal point one time to the left and increase the exponent by one, so we get:

$6.404*10^8$

Then we conclude that the correct option is the last one (where I rounded the expression to only 3 values after the decimal point).

If you want to learn more about scientific notation:

brainly.com/question/5756316

#SPJ1

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