The population function of the Western Lowland Gorillas can either represent population growth or population decay
<h3>How to model the population</h3>
The question is incomplete, as the resources to model the population of the Western Lowland Gorillas are not given.
So, I will give a general explanation to solve the question
A population function can be represented as:

Where:
- The initial population of the Western Lowland Gorillas is represented by (a)
- The rate at which the population changes is represented by (r)
- The number of years since 2022 is represented by (x)
- The population in x years is represented by (y)
From the question, we understand that the population of the Western Lowland Gorillas decreases.
This means that the rate of the function would be an exponential decay i.e. 1 -r
Take for instance:

By comparison.
a = 2000 and 1 - r = 0.98
The above function can be used to model the population of the Western Lowland Gorillas
Read more about exponential functions at:
brainly.com/question/26829092
Answer:
it is 358
Step-by-step explanation:
Hope this helped have an amazing day!
Answer:
this is only one functions, it means all is correct.
After 1 sec it would be 65 m/s
after 2 sec it would be 55 m/s
after 3 sec it would be 40 m/s
after 4 sec it would be 20 m/s
and so on. The equation for this is
S = 70 - (-5(t)) where s=speed and t=time passed
Angle BDC is given as 38° but not drawn in the figure. Amateurs.
We calculate angle DBC
DBC = 180° - 96° - 38° = 180° - 134°
We won't bother subtracting because we're really after
angle ABD = 180° - DBC = 134°
Now we have a Law of Cosines situation,
AD² = AB² + BD² - 2(AB)(BD) cos ABD
AD = √( 5.8² + 27.3² - 2(5.8)(27.3) cos 134°)
AD ≈ 31.61 m
Answer: 31.6 m