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Firlakuza [10]
3 years ago
11

Tanya has a certain amount of money in her savings account. Each month, for 6 months, she deposits $50 less than her original sa

vings amount. After 6 months, she has a total of $750 in the account. How much money did she have in the account when she began adding money to it?
Mathematics
2 answers:
Anna007 [38]3 years ago
6 0
15 it’s 15 I think you divide
siniylev [52]3 years ago
6 0
I'm not for sure but i think it's 15

explanation:
750 divided by 50 = 15
15 times 50 = 750
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Which expressions represent rational numbers? Check all that apply.
Blizzard [7]

Answer:

they're all rational numbers

Step-by-step explanation:

rational numbers are positive, negative, or zero integers. they can be decimals as well.

first expression = 2.449.... + 3 = 5.449 (yes, it is rational)

second expression = 8 + 0.54545454... = 8.545454... (yes, it is rational)

third expression = 6 + 4.582575... = 10.4582575... (yes, it is rational)

fourth expression = 4 + 13 = 17 (yes, it is rational)

fifth expression = 17.43... + 7 = 24.43.... (yes, it is rational)

sixth expression = 6.6332... + 5 = 11.6332 (yes, it is rational)

8 0
3 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

u=x             dv=e^(2x)\cdot{dx}

du=dx         v=2\cdot{e^(2x)}

\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du

\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx

\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C

We can therefore determine that if x tends to 0 the limit is -1

\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1

5 0
4 years ago
What is the definition of a ray
Elan Coil [88]
Mathematically, a ray is a portion of a line which starts at a point and goes off in a particular direction to infinity.


4 0
3 years ago
Paul owes Paula 35 cents and has a pocket full of 5-cent coins, 10-cent coins, and 25-cent coins that he can use to pay her. Wha
kykrilka [37]
So, what is the case in which he uses the least coins? can he use 1 coin? no, there isn't a 35 cent coin. can he use 2 coins? yes! he can use 25+10 cent coins!

now, the largest number of coins means the coins of the smallest value: so using only 5 cent coins. How many would this be?

we have to divide:

35/5=7

so we would use 7 coins.

And the difference is 5: 7-2 is 5.
6 0
3 years ago
Precipitation for the month of March was 6 ½ inches less than average. In April, the precipitation was 2 ⅜ inches less than aver
deff fn [24]

Answer:

The precipitation for both March and April was 8 7/8 inches below average

Step-by step explanation;

For the month of march, precipitation was 6 1/2 inches less than average

For the month of April, precipitation was 2 3/8 inches left.

Now we want to calculate how many inches less than average was precipitation in both wants

What we simply do here is to add the inches with which they were both left than average in both months

That would be;

6 1/2 + 2 3/8

= 13/2 + 19/8 = (52 + 19)/8 = 71/8 = 8 7/8 inches

7 0
3 years ago
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