Perhaps the most concise way to factor is by "completing the square" which is how the quadratic formula is derived...
x^2+6x+8=0 move constant to other side, subtract 8 from both sides
x^2+6x=-8, halve the linear coefficient, square it, then add that to both sides, in this case (6/2)^2=3^2=9
x^2+6x+9=1 now the left side is a perfect square of the form
(x+3)^2=1 take the square root of both sides
x+3=±√1 subtract 3 from both sides
x=-3±√1
x=-3±1
x=-4 and -2
Since the zeros occur when x=-4 and -2 the factors of the equation are:
(x+2)(x+4)
Answer:
A. csc θ=1/sinθ
Step-by-step explanation:
From SOHCAHTOA,
sine = opposite/ hypotenuse
Cos = adjacent / hypotenuse
Tan = opposite / adjacent
In a right angled triangle, the cosecant of an angle is the length of the hypotenuse divided by the length of the side opposite the angle. This is the inverse of sine , therefore:
Csc Ф = 1/ sinФ
Answer: f=-2
Step-by-step explanation:
math
Answer:
Use the given functions to set up and simplify
f (2). 0
Step-by-step explanation:
Answer:
I will attach the missing drawing with the answer.
9.b)
Plane JKM
Plane JLM
Plane KLM
Step-by-step explanation:
The drawing for this question is missing. I will attach it with the answer.
9.a) Plane JKL is not an appropriate name for the plane because all of three points lie in the same line.
Through a line pass infinite planes. The plane JKL doesn't define a unique plane. That's why plane JKL isn't an appropriate name for the plane.
9.b) We can name the plane using three points that don't lie in the same line.
Three possible names for the plane are :
Plane JKM
Plane JLM
Plane KLM