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WARRIOR [948]
3 years ago
9

Suppose D has a coordinate of 11 and DE = 5. What are the possible midpoints of DE?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
6 0

Answer:

(5.5,8) and (5.5,3) are the possible midpoints

<em></em>

Step-by-step explanation:

Given

D = 11

DE = 5

Required

Determine the midpoint of DE

First, we need to determine the coordinates of E

If E is at the right of DE, then

D - E = 5

11 - E = 5

E = 11 - 5

E = 6

Hence,

(D,E) = (11,6)

<em>Calculate Midpoint</em>

Midpoint = \frac{1}{2} * (11,6)

Midpoint = (5.5,3)

Else:

E - D = 5

E - 11 = 5

E = 11 + 5

E = 16

Hence,

(D,E) = (11,16)

<em>Calculate Midpoint</em>

Midpoint = \frac{1}{2} * (11,16)

Midpoint =  (5.5,8)

<em>(5.5,8) and (5.5,3) are the possible midpoints</em>

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Answer:

An hour and 30 minutes.

Step-by-step explanation:

In one hour, they travel 8 kilometers. They then have 4 kilometers left. 4 is half. of 8, so I would possibly take half the time it would to travel 8, making it 30 minutes for the other 4 kilometers.

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Nancy has nine books and she has read 8 total books Sally has two times more books the Nancy how many books does Sally have
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(ab^2 x -b^4a^3)^2<br><br> What is the answers
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Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2

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=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2

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Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

3 0
2 years ago
I need help please.
sweet-ann [11.9K]

Answer:

<u>Third Option</u>: y = \frac{5}{4}x

Step-by-step explanation:

Given the points on the graph, (4, 5) and (-4, -5):

In order to determine the equation of the given graph in slope-intercept form, y = mx + b:

Use the given points to solve for the slope:

Let (x₁, y₁) = (-4, -5)

(x₂, y₂) = (4, 5)

m = (y₂ - y₁)/(x₂ - x₁)

m = \frac{5 - (5)}{4 - (-4)}  = \frac{5 + 5}{4 + 4}  = \frac{10}{8} = \frac{5}{4}

Therefore, the slope of the line is: m = \frac{5}{4}.

Next, use one of the given points on the graph, (4, 5) to solve for the y-intercept, b:

y = mx + b

5 = \frac{5}{4} (4) + b

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0 = b

Therefore, the linear equation in slope-intercept form is: y = \frac{5}{4}x.  The correct answer is Option 3.

8 0
2 years ago
13. In A ABC, if m BF is an angle bisector, find<br> m
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If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.

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Angle bisector basically divides an angle into two parts.

If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.

In this way ∠ABC=2*∠ABF

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∠BCE=180-172

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Learn more about angles at brainly.com/question/25716982

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