Answer:
Step-by-step explanation:
no of days no of men
30 20
24 20
30/24=x/20
24 x=30*20
24x=600
x=600/24
x=25
therefore 5 more men are needed to complete the work in 24 days
Answer:
Her model is 37 times as tall as Ben's.
Step-by-step explanation:
70 11/12 ÷ 5 3/4
851/12 ÷ 23/4
851/12 x 4/23
37/1 x 1/1 = 37 times as tall
The answer to this question is the school is going to have to rent 2 vans extra. The reason is because each van hols 8 people right. for the 6 vans that the school already owns, that will be 48 students in vans. When you subract that from 59, you get 11 students that still need a van, so 11 students can not fit in one extra van so the school would need two. Hope this gives you what you were looking for. God bless, and hope this helped. Also, please let me know if it was correct.
Answer:
39.13 units²
Step-by-step explanation:
Height of the triangle:
10cos(30) = 5sqrt(3)
Radius = ⅓(5sqrt(3)) = 5sqrt(3)/3
Triangle - circle
[½(10)(10)sin60] - [(3.14)(5sqrt(3)/3)²]
43.30127019 - 4.166667
39.13460352 unitsw
Answer:
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
Step-by-step explanation:
Let the random variable Y have a geometric distribution g (y;p) = pq y-¹
The m.g.f of the geometric distribution is derived as below
By definition , M₀ (t) = E (e^ ty) = ∑ (e^ ty )( q ^ y-1)p ( for ∑ , y varies 1 to infinity)
= pe^t ∑(e^tq)^y-1
= pe^t/1- qe^t, where qe^t <1
In order to differentiate the m.g.f we write it as
M₀ (t) = p / e^-t -q = p (e^-t -q) ^ -1
M₀` (t) = pe^-t (e^-t -q) ^ -2 and
M₀^n(t) = 2pe^-2t (e^-t -q) ^ -3 - pe^-t (e^-t -q) ^ -2
Hence
E (y) = p (1-q)-² = 1/p
E (y²) =2 p (1-q)-³ - p (1-q)-²
= 2/p² - 1/p and
σ² = [E (y²) -E (y)]²
= 2/p² - 1/p - (1/p)²
= q/p²
