Answer:
H0: σ² = 0.0016 against the claim
H1: σ² ≠ 0.0016
Step-by-step explanation:
The claim is the alternative hypothesis . If we have the alternative hypothesis that variance is not equal to 0.0016. Then the null hypothesis would
H0: σ² = 0.0016 against the claim
H1: σ²≠ 0.0016
This is a two tailed test.
The null hypothesis is opposite to the claim stated. The claim is the alternative hypothesis.
By knowing the alternative hypothesis one can find the null hypothesis.
The claim is that the variance of the number of accidents per day is no longer equal to 0.0016.
The claim is H1: variance≠ 0.0016 or
H1= σ²≠ 0.0016
Therefore the null hypothesis is
H0: σ²=0.0016
8×25=200
and
200×23=4600
so 8×25×23=4600
Answer:
16
Step-by-step explanation:
A right angle has the measurement of 90°. Set the expression equal to 90:
5x + 10 = 90
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 10 from both sides:
5x + 10 (-10) = 90 (-10)
5x = 90 - 10
5x = 80
Next, divide 5 from both sides:
(5x)/5 = (80)/5
x = 80/5
x = 16
16 is your possible value.
~
Answer: Height: 24.9 inch, Width: 44.3 inch
Step-by-step explanation:
Check the picture below, so the green line is really the radius of the circle, and we know its center.
![~~~~~~~~~~~~\textit{distance between 2 points}\\\\(\stackrel{x_1}{0}~,~\stackrel{y_1}{-3})\qquad(\stackrel{x_2}{\frac{15}{2}}~,~\stackrel{y_2}{1})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\\stackrel{radius}{r}=\sqrt{[\frac{15}{2} - 0]^2 + [1 - (-3)]^2}\implies r=\sqrt{\left( \frac{15}{2} \right)^2 + (1+3)^2}\\\\\\r=\sqrt{\left( \frac{15}{2} \right)^2 +4^2}\implies r=\sqrt{\frac{225}{4} + 16}\implies r=\sqrt{\cfrac{289}{4}}\implies r=\cfrac{17}{2}\\\\[-0.35em]\rule{34em}{0.25pt}](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%5C%5C%28%5Cstackrel%7Bx_1%7D%7B0%7D~%2C~%5Cstackrel%7By_1%7D%7B-3%7D%29%5Cqquad%28%5Cstackrel%7Bx_2%7D%7B%5Cfrac%7B15%7D%7B2%7D%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%5Cqquad%20%5Cqquadd%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%5C%5C%5C%5C%5C%5C%5Cstackrel%7Bradius%7D%7Br%7D%3D%5Csqrt%7B%5B%5Cfrac%7B15%7D%7B2%7D%20-%200%5D%5E2%20%2B%20%5B1%20-%20%28-3%29%5D%5E2%7D%5Cimplies%20r%3D%5Csqrt%7B%5Cleft%28%20%5Cfrac%7B15%7D%7B2%7D%20%5Cright%29%5E2%20%2B%20%281%2B3%29%5E2%7D%5C%5C%5C%5C%5C%5Cr%3D%5Csqrt%7B%5Cleft%28%20%5Cfrac%7B15%7D%7B2%7D%20%5Cright%29%5E2%20%2B4%5E2%7D%5Cimplies%20r%3D%5Csqrt%7B%5Cfrac%7B225%7D%7B4%7D%20%2B%2016%7D%5Cimplies%20r%3D%5Csqrt%7B%5Ccfrac%7B289%7D%7B4%7D%7D%5Cimplies%20r%3D%5Ccfrac%7B17%7D%7B2%7D%5C%5C%5C%5C%5B-0.35em%5D%5Crule%7B34em%7D%7B0.25pt%7D)
![\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{0}{ h},\stackrel{-3}{ k})\qquad \qquad radius=\stackrel{\frac{17}{2}}{ r} \\\\\\\ [x-0]^2~~ + ~~[y-(-3)]^2~~ = ~~\left( \cfrac{17}{2} \right)^2\implies x^2+(y+3)^2 = \cfrac{289}{4}](https://tex.z-dn.net/?f=%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%20%5Cqquad%20center~~%28%5Cstackrel%7B0%7D%7B%20h%7D%2C%5Cstackrel%7B-3%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20radius%3D%5Cstackrel%7B%5Cfrac%7B17%7D%7B2%7D%7D%7B%20r%7D%20%5C%5C%5C%5C%5C%5C%5C%20%5Bx-0%5D%5E2~~%20%2B%20~~%5By-%28-3%29%5D%5E2~~%20%3D%20~~%5Cleft%28%20%5Ccfrac%7B17%7D%7B2%7D%20%5Cright%29%5E2%5Cimplies%20x%5E2%2B%28y%2B3%29%5E2%20%3D%20%5Ccfrac%7B289%7D%7B4%7D)