15 points for who helps! Need answer fast!

The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest

Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

$P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)$

Calculation the value from standard normal z table, we have,

$P(x < 5) =0.7287= 72.87\%$

b) P( port handles 3 or more million tons of cargo per week)

$P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)$

Calculating the value from the standard normal table we have,

$1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%$

c)P( port handles between 3 million and 4 million tons of cargo per week)

$P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%$

$P(3 \leq x \leq 4) = 23.7\%$

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85$

$= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85$

$=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15$

Calculation the value from standard normal z table, we have,

$P( z \leq -1.036) = 0.15$

$\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65$

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0

3 years ago

Which diagram represents the postulate that states exactly one line exists between any two points?

Ivahew [28]

Answer:

C with points A and B on the line

5 0

3 years ago

Read 2 more answers

How do I solve this equation? Please, if you will, explain.

Licemer1 [7]

Yes, but your answer will be a decimal, but make sure you check your work and one way you can check your work is by first combing like terms, and then solve it as it is an equation.

7 0

3 years ago

Read 2 more answers

Marymount Township secured the construction of a power plant, which opened in 1990. Once the power plant opened

Aleksandr [31]

Answer:

92087,14873

Step-by-step explanation:

Given that Marymount Township secured the construction of a power plant, which opened in 1990. Once the power plant opened in 1990, the population of Marymount increased by about 20% each year for the first ten years and then increased by 5% each year after that

Let P0 be the population in 1990

Then we have in 2000 the population is

$P(2000) = P_0(1.2)^{10}$

with this initial population for next growth we have in 2010 the population would be

$P(1.05)^{10}$ , where P = population is 2000

a) Given that $P(1.05)^{10) = 150000\\P = 150000(1.05)^{-10} =92.086.99\\=92087$

b) we use the exponential equation and solve for initial population in 2000.

c) we have

$P_0(1.2)^{10} =92087\\P_0 = 92087((1.2)^{-10})\\=14872.56\\=14873$

6 0

3 years ago

A field hockey team wins 80% of its games. Based on your simulation, what is the experimental probability of the team winning it

ElenaW [278]

The probability that they will win their next three games is 51.2%.

The chance that they win is 80%. To find the probability that they win 3 games in a row, we just have to multiply 80% by itself 3 times.

0.8 x 0.8 x 0.8 = 0.512 = 51.2%

6 0

3 years ago