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cluponka [151]
3 years ago
14

Suri's age is 4 less than 3 times her cousin's age. Suri is 17 years old. Which method can be used to find c, her cousin's age?

Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

7 years

Step-by-step explanation:

Suri's age=17 years

Her cousin's age =c

Suri's age is 4 less than 3 times her cousin's age

4 less than 3 times her cousin's age means subtract 4 from 3 times her cousin's age

17=3c - 4

Find c which is her cousin's age

Add 4 to both sides

17+4=3c - 4 + 4

17+4=3c

21=3c

Divide both sides by 3

21/3=3c/3

7=c

Therefore,

C= 7

Her cousin's age = 7 years

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A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

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2 years ago
Two litters of a particular rodent species have been born, one with two brownhaired and one gray-haired (litter 1), and the othe
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Answer:

a. So probability that the animal chosen is brown-haired = 0.633

b. Given that a brown-haired offspring was selected, probability that the sampling was from litter1 = P(B|A) = 0.5263.

Step-by-step explanation:

Being that We are given,event of Brown hair with two disjoint events, one is { ( BrownHair ) ∩ ( Litter 1) } and the other is { ( BrownHair ) ∩ ( Litter 2) } .

a) To find the probability that the animal chosen is brown-haired,

Let A : we choose a brown-haired rodent and B : we choose litter1.

So using the axioms of probability, we can write

P(A) = P(A | B) * P(B) + P(A | Bc) * P(Bc)

Making use of the given information, we get;

number of brown haired rodents in litter 2 P(AB) Total number of rodents in litterl

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P(A |B^{c}) =\frac{\text{number of brown haired rodents in litter2}}{\text{Total number of rodents in litter2}}= \frac{3}{5}

And also it is given that we choose litter at random ,so P(B) = P(Bc ) = 1/2

So now we plug these values in the equation of P(A) and get

P(A) = (\frac{2}{3}*\frac{1}{2}) + (\frac{3}{5}*\frac{1}{2}) = \frac{2}{6}+\frac{3}{10} = 0.633

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Lets make use of Bayes rule to find this conditional probability,

So using theorem we get,

P(B|A) = \frac{P(A|B)*P(B)}{P(A|B)*P(B)+P(A|B^{c})*P(B^{c})}

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Absolute values are positive version of any number. So the absolute value of both 0.2 and -0.2 would be 0.2

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