Please help me! i don't understand how 5x^2-12x-27=0 can be proven with the diagram

Mathematics

1 answer:

ira [324]3 years ago

3 0

X=(6+3\sqrt(19))/(5),(6-3\sqrt(19))/(5)
x=3.81533936,-1.41533936

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3n+75=50+2n please help righting more

alexandr1967 [171]

Answer: n = -25

Step-by-step explanation:

you would need to get N by itself so you would subtract 2n from both sides and that would bring you to n+75=50 and then you would need to subtract 75 from both sides and that leads you to n=-25

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3 years ago

Rectangle ABCD has vertex coordinates A(1,-2), B(4, -2), C(4,-4), and D(1,

dimulka [17.4K]

Answer:(7,-3)

Step-by-step explanation:

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2 years ago

X+y=14; 2x-2y=14 inconsistant, dependent or neither

hammer [34]

You looking for x and y right ?

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3 years ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

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3 years ago

What is the value of p?

Misha Larkins [42]

P=pie which could be 8

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3 years ago