Is the function even, odd, or neither?

Mathematics

1 answer:

goblinko [34]3 years ago

8 0

Answer:

A function with a graph that is symmetric about the origin is called an odd function. Note: A function can be neither even nor odd if it does not exhibit either symmetry. For example, f(x)=2x f ( x ) = 2 x is neither even nor odd

Step-by-step explanation:

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the area of a right triangle is 336 square centimeters. The base of the right triangle is 48 centimeters. What is the length of

Alex73 [517]

Answer:

50 cm

Step-by-step explanation:

So the first step is to find the height, and to do that you know that the area of a triangle is height * base / 2 = area. Plugging in the numbers you have, you get:

$height*48/2=336$

Then, this becomes

$height * 24 = 336$

Divide both sides by 24

$height = 14$

Now you can use the base and the height to find the hypotenuse using the Pythagorean Theorem: $a^{2} +b^{2} =c^{2}$

$48^{2} +14^{2} =c^{2} \\2304 + 196 = c^{2}\\2500 = c^2\\50 = c\\c = 50$

Therefore the length of the hypotenuse is 50 cm

8 0

2 years ago

The range of 3, 5, 1, 2, 4, 6, 0, 2 is *

Scrat [10]

Answer:

6-0=6

Step-by-step explanation:

you take the highest number subtract the lowest answer

6 0

3 years ago

Read 2 more answers

√(25 - 10 √(3) + 3)<br> (not as a decimal)

nikitadnepr [17]

Answer:

$\huge\boxed{\sqrt{25-10\sqrt3+3}=5-\sqrt3}$

Step-by-step explanation:

$\sqrt{25-10\sqrt3+3}=(*)\\\\25=5^2\\3=(\sqrt3)^2\\10\sqrt3=(2)(5)(\sqrt3)\\\\(*)=\sqrt{5^2-(2)(5)(\sqrt3)+(\sqrt3)^2}\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=\sqrt{(5-\sqrt3)^2}\\\\\text{use}\ \sqrt{a^2}=|a|\\\\=|5-\sqrt3|=5-\sqrt3\\\\^{\text{because}\ 5>\sqrt3\to5-\sqrt3>0}$