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3 years ago

What percent is modeled by the grid?

Mathematics

2 answers:

Rainbow [258]3 years ago

3 0

Answer:

33%

Step-by-step explanation:

There are 33 squares out of 100 that are shaded

33/100

Percent means out of 100

33%

zhuklara [117]3 years ago

3 0

Answer: 33%

Explanation: A ratio that compares a number to 100 can be written as a percent. So in this problem, since the figure has 33 out of 100 boxes shaded, we have the ratio 33/100 which can be written as 33%.

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Answer:

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3 years ago

What is 1/3 divided by 1/9

Viktor [21]

.333333/.11111111 = 3

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4 years ago

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Determine, to one decimal place, the length, width & height of the rectangular prism that would have the greatest volume, wi

Leya [2.2K]

Answer:

The length = The width = The height ≈ 5.8 cm

Step-by-step explanation:

The volume of a rectangular pyramid, V = l × w × h

The surface area of the pyramid = 2 × l × h + 2 × w × h + 2 × l × w = 200

∴ l × h + w × h + l × w = 200/2 = 100

We have that the maximum volume is given when the length, width, and height are equal and one length is not a fraction of the other. Therefore, we get;

At maximum volume, l = w = h

∴ l × h + w × h + l × w = 3·l² = 100

l² = 100/3

l = 10/√3

Therefore, the volume, v = l³ = (10/√3)³

The length = The width = The height = 10/√3 cm ≈ 5.8 cm

7 0

3 years ago

Help me determine if this function is even or odd!

11Alexandr11 [23.1K]

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2 years ago

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I need help in partial fraction!! With simple explaination would be nice!

WITCHER [35]

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}$

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}$

Now the second term can be decomposed into partial fractions.

$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}$
$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}$
$4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)$
$4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1$
$\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3$
$\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}$

So

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}$

3 0

3 years ago