The absolute value of -8 is 8 and the absolute value of 5 is 5. Absolute value is basically the number's distance from 0 on a number line, basically how many numbers it is away from 0. For that reason, it's always positive, regardless of whether or not the number is positive or negative. Hope this helped!
Answer:
y =
+ 
Step-by-step explanation:
y''- 9 y' + 18 y = t²
solution of ordinary differential equation
using characteristics equation
m² - 9 m + 18 = 0
m² - 3 m - 6 m+ 18 = 0
(m-3)(m-6) = 0
m = 3,6
C.F. = 
now calculating P.I.


hence the complete solution
y = C.F. + P.I.
y =
+ 
Answer:
I think it is correct
Step-by-step explanation:
length=10m
height=12
breadth = 3m
volume = l*b*h
10*12*3
120*3
360m^3
Answer:
There are 36 cubes
Step-by-step explanation: