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3 years ago

I’ll give brianliest

Mathematics

1 answer:

avanturin [10]3 years ago

6 0

Answer:

if its area its 21,504 but if its perimiter its 33

Step-by-step explanation:

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The area under the normal curve between z = 0 and z = 1 is __________ the area under the normal curve between z = 1 and z = 2.

Lena [83]

Answer:

greater than

hope this helps! <3

7 0

2 years ago

If P(A) = 0.25, then the probability of the complement of A is

djverab [1.8K]

Answer:

P(A') = 0.75

Step-by-step explanation:

We are given that the probability P(A) = 0.25 and we are to determine the probability of the complement of A.

According to the Complement Rule of any probability, the sum of the probabilities of an event and its complement must be equal to 1.

So for for the event A,

P(A) + P(A') = 1

0.25 + P(A') = 1

P(A') = 1 - 0.25

P(A') = 0.75

8 0

3 years ago

for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation

Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample proportion of defective items = 12,898

s = sample standard deviation = 7,719

n = sample size = 5

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.776 < $t_4$ < 2.776) = 0.95 {As the critical value of t at 4 degrees of

freedom are -2.776 & 2.776 with P = 2.5%}

P(-2.776 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.776) = 0.95

P( $-2.776 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,898-2.776 \times {\frac{7,719}{\sqrt{5} } }$ , $12,898+2.776 \times {\frac{7,719}{\sqrt{5} } }$ ]

= [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0

4 years ago

Please help numbers 1 through 5.

ser-zykov [4K]

Answer:

i can't see

Step-by-step explanation:

4 0

3 years ago

Verify that (a+b)+c = a+ (b+c) by taking a = -8 , b = (-8/11) , c = (-8/12)

gogolik [260]

Answer:

Step-by-step explanation:

$(-8+-\frac{8}{11} ) + (-\frac{8}{12}) = -\frac{96}{11} + (-\frac{2}{3}) = -\frac{288 + 22}{33}) = -\frac{310}{33}\\ (-8) + (-\frac{8}{11} + (-\frac{2}{3})) = (-8) + (-\frac{46}{33})= -\frac{310}{33}$

6 0

4 years ago

Read 2 more answers