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2 years ago

Nth term of a sequence is 2n-6 find out first three terms

Mathematics

1 answer:

defon2 years ago

5 0

The first term: a1 = -4
The second term: a2 = −2
The third term: a3 = 0

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If one of the roots of the equation x²- 4x + k=0exceeds the other by 2, then find the roots and determine the value of k

BaLLatris [955]

Answer:

roots: 1 and 3

k = 3

Step-by-step explanation:

2 roots: p and p+2

(x-p) (x-p-2) = x² - 4x + k

x² -2px -2x + p² + 2p = x² - 2 (p+1)x + (p² + 2p) = x² -4x + k

-2 (p+1) = -4

p+1 = 2

p = 1 ... root 1

p' = 1+2 = 3 ... root 2

k = p² + 2p = 3

check: (x-1) (x-3) = x² - 4x + 3 = x² - 4x + k

6 0

2 years ago

What is the answer for this

Lady bird [3.3K]

The equation that represents this hanger is: 4w=25

The weight of one circle is: 6.25

7 0

3 years ago

Simplify the following math expression: 5+4(6-3)+4/2

lesantik [10]

Answer:

you have to solve the brackets first(6-3=3)

Then solve the division (4/2=2)

lastly the addition (5+4=9)

so we have 9×3=27

27+2=29.

3 0

2 years ago

Read 2 more answers

In 2000, the population of Massachusetts

Zepler [3.9K]

Answer:

The population reaches 7 million people in the year 2032.

Step-by-step explanation:

We have that

$f(x) = 6.3*(1.0032)^{x}$

Using this model, find the year when the population reaches 7 million people.

This is x years after 2000, in which x is found when f(x) = 7. So

$f(x) = 6.3*(1.0032)^{x}$

$7 = 6.3*(1.0032)^{x}$

$(1.0032)^{x} = \frac{7}{6.3}$

$(1.0032)^{x} = 1.11$

We have to following logarithm rule

$\log{a^{x}} = x\log{a}$

So we apply log to both sides of the equality

$\log{(1.0032)^{x}} = \log{1.11}$

$x\log{1.0032} = \log{1.11}$

$x = \frac{\log{1.11}}{\log{1.0032}}$

$x = 32.66$

2000 + 32.66 = 2032

The population reaches 7 million people in the year 2032.

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2 years ago

Use the graph below to write the equation of the function

Ksivusya [100]

Answer:

Step-by-step explanation:

gefhhfeyjhtwgi15287

8 0

3 years ago